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MaRussiya [10]
2 years ago
9

5) What is the pressure of a 3 moles of oxygen in a 5 liter container at 300

Mathematics
1 answer:
blondinia [14]2 years ago
7 0

Answer:

1496.52 Pa, 14.76 atm

Step-by-step explanation:

This question can be solved using ideal gas law

according to which

pv = nrt

where p is the pressure of gas

v is volume of gas

n is amount gas in moles

R is ideal gas constant whose value is 8.314 J/mol

T is absolute temperature of gas on Kelvin scale

______________________________

given

v = 5 liter

n = 3

T = 300 kelvin

R = 8.314 J/mol

Let the pressure be p

Substituting the above value in ideal gas law equation we have

p*5 = 3*8.314*300

p = 7482.6/5 = 1496.52 Pa

This pressure is in pascal while option is in atm

we know 1 Pascal is equal to 0.0000098692 atm

we know that 1 Atm = 101325 Pa

thus, 1496.52 is equal to  0.0000098692*1496.52 atm

1496.52 is equal to 14.76 atm

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What is the 32nd term of 311, 305, 299
nata0808 [166]

Answer:

503

Step-by-step explanation:

For an arithmetic sequence, the n-th term is found by

a_n = a_1 + (n - 1)d

To find d (the common difference) we can simply subtract one of the terms by the last, for example:

d = 299 - 305 \\d = -6 \\

The common difference must be the same throughout the entire sequence, so we can do it once more just to be sure:

d = 305 - 311\\d = -6

We also have to know that a_1 stands for the first term of the sequence, which in this case is 311.

Now that we know this, let's find the 32nd term

a_{32} = 311 + (32 - 1)-6\\a_{32} = 311 + 192\\a_{32} = 503

Good luck!

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Step-by-step explanation:

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