The altitudes of equal length, BE and CF gives AB = AC, from which we have;
- ∆ABC is an isosceles triangle
<h3>How can the RHS rule be used to indicate an isosceles triangle?</h3>
From the given description, we have;
BE = CF
<CFB = <BEC = 90° All right angles are congruent
BC = BC by reflexive property of congruency
BC = The hypotenuse side of triangles ∆BFC and ∆CEB
Therefore;
∆BFC is congruent to ∆CEB by Right angle Hypotenuse Side, RHS, rule of congruency.
Therefore;
BF = CE by Corresponding Parts of Congruent Triangles are Congruent, CPCTC
Similarly, we have;
∆AEB is congruent to ∆AFC, by Side-Angle-Angle, SAA, rule of congruency
Which gives;
FA = AE by CPCTC
BF + FA = CE + AE, by substitution property of equality
BF + FA = AB
CE + AE = AC
Therefore;
Therefore;
- ∆ABC is an isosceles triangle
Learn more about rules of congruency here:
brainly.com/question/24261247
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Answer:

Step-by-step explanation:
Take two points from the graph
(0,24) and (6,12)
Find the slope
The formula to calculate the slope between two points is equal to

substitute

---> is negative because is a decreasing function
Find the equation of the line in slope intercept form

we have

Note: The y-intercept is given (0,24)
substitute

Ahh this is a good hard question, I hope someone comes along and helps. Goodluck my friend!
The answer is -6
Because when x = -2, y = -6 on the graph
Answer:
7 square units
Step-by-step explanation:
Two of the points are on the horizontal line y = -3, so it is convenient to call that the "base" of the triangle. The length of the base is the difference in the x-coordinates of its end points:
b = 3 -(-4) = 7
The height is measured perpendicular to the base, so is the vertical distance from the line y=-3 to the third point. That distance is the difference between -3 and the y-coordinate of point A:
-3 -(-5) = 2
The triangle has a base of length 7 and a height of 2. Its area is ...
A = 1/2bh
A = 1/2(7)(2) = 7 . . . . square units