The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
Your answer is going to be B. $14.75, hope this helps!!
Answer:
87
Step-by-step explanation:
earning rate (R) = $5/hr
total (T) = $287
time (t) = 40 hr
tips = T - Rt
= $287 - $5*40
$87
Answer:
question no:3
Step-by-step explanation:
here
= x^2 + 5x - 300
= x^2 +(20-15)x -300
= x^2 + 20x - 15x - 300
= x(x+20) -15(x+20)
= (x+20) (x - 15)
Answer:
The total area of the pool section of Keith's backyard is 390 square feet.
Step-by-step explanation:
Since Keith is trying to figure out the area of his pool section in his backyard, and he knows that his pool is 20 feet long and 9 feet wide, and he also knows the sidewalk is 3 feet wide all around the floor, to determine what is the total area of the pool section of Keith's backyard, the following calculation must be performed:
(20 + 3 + 3) x (9 + 3 + 3) = X
26 x 15 = X
390 = X
Therefore, the total area of the pool section of Keith's backyard is 390 square feet.
