Question

Picture picture picture

Answer 1

Soo what do you need help with? It seems pretty easy. I can help you if you want.

Answer 2

Answer:

a) Dot plot on hours of TV: Please see the picture below, the data are approximately symmetric.

b) Mean = 2 hours of TV

c) Median = 0.305 coins

   Mean = 0.585 coins

d) Median

Step-by-step explanation:

a) To draw the dot plot, you need to sort the data smallest to largest, so you have:

0  1  1  2  2  2  3  3  4  4

Then you put in the draw one point for value you find. You can see in the draw one point for zero because is only once, two points for the one because there are two data with the value one, three dots for the two becase there are three datas with the value two, and two dots for numbers three and four because they are repeated twice in the dataset.

You can see that the distribution is approximately symmetric because there are approximately the same quantity of dots in each number.

b) As you have an approximately symmetric distribution on the data, you should use the mean to describe a typical number of hours of TV watched by the students.

So to calculate the mean you need to add up all the data and divide by how many data there are:

$Mean = \frac{0+1+1+2+2+2+3+3+4+4}{10}$

$Mean=\frac{22}{10}$

$Mean=2.2$

And round the result to an integer we have that Mean=2 hours of TV

c) Calculate of the median:

To calculate the median of the data that represent the total value of coins which has each student, you need to sort the data smallest to largest:

0.00   0.00   0.10   0.15   0.25   0.36   0.54   0.89   1.37   2.19

Now you need to find the data in the middle, in this case we have an odd set of data, so there are two data in the middle: 0.25 and 0.36, so to calculate the median, we need to find de mean between those numbers:

$Median=\frac{0.25+0.36}{2}$

Median = 0.305 coins

Calculate of the mean:

To calculate the mean of the data you need to add up all the numbers and divided by the number of data, that is:

$Mean=\frac{0.00+0.00+0.10+0.15+0.25+0.36+0.54+0.89+1.37+2.19}{10}$

$Mean=\frac{5.85}{10}$

Mean = 0.585 coins

d) The values of the mean and the median are so different because the majority of numbers are smaller than one, but there are two values that are greater than one, so that indicates that the dataset is not symmetric.

For that reason, we need to use the Median to find the value of a typical value of coins for these ten students.