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ICE Princess25 [194]

3 years ago

9

A man travels a distance of 20 miles at 60 miles per hour then returns over the same route at 40 miles per hour. Find the averag

e rate per hour.
A)50
B)48
C)47
D)46

1 answer:

elena55 [62]3 years ago

7 0

Average = (60 miles per hour + 40 miles per hour)/ 2 = 5<span>0 miles per hour
</span><span>average rate per hour = 50

answer
50</span>

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Answer:

Step-by-step explanation:

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3 years ago

Connor wants to drive from Tucson to the Grand Canyon a distance of 338 miles if he drives a steady rate of 52 mph how many hour

alexandr1967 [171]

Answer:

6.5 Hours

Step-by-step explanation:

Divide 338 by 52 to get the answer

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Use the fact that the length of an arc intercepted by an angle is proportional to the radius to find the arc length given that r

Komok [63]

Answer:

The required length is 37.68 cm

Step-by-step explanation:

We have given the radius of which is 3 cm and $\theta$ which is $\pi\cdot 4$

We will use $\pi=3.14$

We know the formula for length of arc which is:

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We will substitute the values given we will get:

$length=3(3.14)(4)$

$length=37.68$

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3 years ago

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A bag contains 10 white golf balls and six striped golf balls a golfer wants to add 112 golf balls to the bag he wants the ratio

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4 years ago

the name Joe is very common at a school in one out of every ten students go by the name. If there are 15 students in one class,

kumpel [21]

Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.

For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.

<h3>Binomial probability distribution </h3>

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

One in ten students are named Joe, hence $p = \frac{1}{10} = 0.1$ .

There are 15 students in the class, hence $n = 15$ .

The probability that at least one of them is named Joe is:

$P(X \geq 1) = 1 - P(X = 0)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059$

Then:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2059 = 0.7941$

0.7941 = 79.41% probability that at least one of them is named Joe.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

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3 years ago