Step-by-step explanation:
perdon no entindo
Answer:
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Step-by-step explanation:
Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.
Let five years ago be group I X and as of now be group II Y
(Two tailed test at 5% level of significance)
Group I Group II combined p
n 270 300 570
favor 120 140 260
p 0.4444 0.4667 0.4561
Std error for differene = 
p difference = -0.0223
Z statistic = p diff/std error = -1.066
p value =0.2864
Since p value >0.05, we accept null hypothesis.
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Answer:
Yes
Step-by-step explanation:
In the equation, -1.3 is the y-intercept. The y-intercept always has a x value of 0. On the point (0,-1.3), it matches the y-intercept and is therefore part of the function/equation.
Hope this helps :)
Answer:
24 times
Step-by-step explanation:
cone is used to fill cylinder
conevolume times x=cylindervolume
so
x=cylinderv/conev
cylinderv=hpir^2
conevolume=1/3hpir^2
cylinder:
v=hpir^2
r=10
h=20
v=20*pi*10^2=2000π
cone=1/3hπr²
r=5
h=10
v=1/3(10)π5²=250π/3
volume of cylinder ÷ volume of cone
= 2000π ÷ (250π÷3)
= 6000π ÷ 250π
= 600÷25
= 24
please mark me brainliest
First, let's see if we can rewrite this word problem a little bit more mathematically. We won't get to mathy or technical so no worries. We just want to look at it in a more straightforward way, if we can.
Train A's mph plus Train B's mph summed equal 723.5 mph. Train A's mph is greater than Train B's mph by 12.5 mph.
So what should we do to solve this problem? Since we are dealing with two of something and we know the value of the two combined, it might make sense to start by dividing that value by 2.
723.5 / 2 = <em /> 361.75. If the two trains were travelling at the same speed, we would be done. Unfortunately, they are not so we need to think about this some more.
Train A is going 12.5 mph faster than Train B. Let's rewrite.
Train A mph = 12.5 + 361.75 = 374.25 Okay, so Train A is travelling at a speed of 374.25 mph. So we're done right? Not exactly. We are asked to fing the speeds of BOTH trains. How do we find the speed of Train B? We have added a portion of the combined total to Train A. It seems to follow, then, we should probably subtract the same portion from Train A. What are we going to do? You guessed it! Rewrite.
Train B mph = 361.75 - 12.5 = 349.25 HA HA! We seem to have figured it out. Let's do one last thing to check our work. Let's add the two trains' speeds together. If we did this right, we should get our summed value of 723.5 mph
374.25 + 349.25 = 723.5
Pat yourself on the back! We did it!
374.25 + 349.25 =
