Answer: 2.28%
Step-by-step explanation:
Given: An airport find that at the present time, the mean noise level is 103 decibels and the standard deviation is 5.4 decibels.
The distribution of noise levels(x) for all jets during takeoff over the neighborhood has a normal distribution.
The probability that jets have a noise level less than 92.2 decibels when taking off over this neighborhood will be :-

Hence, the percent of these jets have a noise level less than 92.2 decibels when taking off over this neighborhood = 2.28%
Answer:
The answer is 0
Step-by-step explanation:
3n(3m-2n) + 6m^2= (6m-3n)(2n+m)
By expansion
9mn - 6n^2 + 6m^2 = 12mn + 6m^2 -6n^2 - 3mn
By collecting like terms
9mn - 12mn + 3mn - 6n^2 + 6n^2 + 6m^2 - 6 m^2 = 0
-3mn + 3mn=0
Therefore the simplification of the expansion gives us 0
Answer:
30 dogs
Step-by-step explanation:
There are 40 cats, and 25% more cats than dogs. If you find 25% of 40, you get 10. That means there are 10 more cats than dogs. 40-10= 30.
30 dogs.
Answer:
if i'm not mistaken it's A