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2 years ago

10

HELPPP MEEEEE PLEASE ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️ BRAINLESTTTTTT . + POINTS ‼️‼️‼️‼️‼️‼️+ thank you ‼️‼️‼️‼️‼️‼️‼️‼️‼️ please help

meeeee out the kindness of your hearttt ❗️❗️

2 answers:

marusya05 [52]2 years ago

5 0

Store B has the lowest price for bread.

irakobra [83]2 years ago

3 0

Store B, because it’s cheaper.

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Evaluate y/2x-z x=4y=3and z=2

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First you plug in the missing values
y=3 x=4 z=2
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than you solve
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I'm confused about this, please help!

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3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

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Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

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3 years ago

Convert 6 4/5 to an improper fraction

dsp73

6+(4/5)

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