2/-3 by using the formula y2-y1/x2-x1
For this case we must raise an inequality.
We have "d" dollars initially and they are spent 12. Then:
![d-12](https://tex.z-dn.net/?f=d-12)
At least 51 dollars remain, then, the sign of inequality is greater or equal in favor of the expression
, that is:
![d-12\geq 51](https://tex.z-dn.net/?f=d-12%5Cgeq%2051)
Resolving:
![d\geq 51 + 12\\d\geq 63](https://tex.z-dn.net/?f=d%5Cgeq%2051%20%2B%2012%5C%5Cd%5Cgeq%2063)
There are at least 63 dollars left in the account.
Answer:
![d-12\geq 51\\d\geq 63](https://tex.z-dn.net/?f=d-12%5Cgeq%2051%5C%5Cd%5Cgeq%2063)
28 is the least common multiple. To find the least common multiple, you look through the numbers both 4 and 7 go into. The smallest of those number is the least common multiple, or LCD.
We get all these to have the same denominators for all the fractions.
2*2/9*2 = 4/18
1*2/9*2 = 2/18
1*3/6*3 = 3/18
Now we can add all the numerators.
4/18 + 2/18 + 3/18 = 9/18
Simplify our answer by dividing both numbers by 3, then by 2.
9/3 and 18/3 = 3/6= 1/2
Our final answer is 1/2