All categories

3 years ago

Meg received a 3% increase in pay, She was making $690/week

Mathematics

2 answers:

jekas [21]3 years ago

8 0

Answer:

$20.70 increase per week!

Step-by-step explanation:

multiply 690 * 0.03 (aka 3%) to get 20.7 which equals $20.70

if you want to know how much she made the next week altogether, add 690 + 20.70 to get $710.70!

quester [9]3 years ago

6 0

Answer:

the answer is $710.70

Step-by-step explanation:

690 x 52 (weeks in a year) = $35,880.00 x 3% = 1076.40

$1,076.40 + $35,880.00 = 36, 956.40 / 52 weeks = 710.70 per week

with the increase she got an additional $20.70 per week.

You might be interested in

Find the value of x in the triangle

Marianna [84]

Answer:

Option D

Step-by-step explanation:

Use the Pythagorean theorem to solve this question

a2+b2=c2

c2 is always the hypotenuse, which is what we have to solve.

3^2+ 5^2=

9+25=34

Now we have to square 34 and there is our answer

6 0

3 years ago

Read 2 more answers

1. The point (–1, 13) is on the terminal side of an angle in standard position. Use this

Masja [62]

Uh i think it’s uhh.... i think it’s a carrot

4 0

3 years ago

An experimenter used the following design for studying five variables in eight runs in four blocks of size 2. (a) By reordering

never [62]

Answer:

A design in which all levels of each independent variable are combined with all levels of the other independent variables. A factorial design allows investigation of the separate main effects and interactions of two or more independent variables.

Step-by-step explanation:

3 0

3 years ago

Neep help as fast as possible. Will mark correct answer brainliest.

Umnica [9.8K]

Answer:

kbohogohohohohohohohop

7 0

3 years ago

Verify a(b-c)=ab-ac for a=1.6;b=1/-2;& c=-5/-7

harina [27]

Given:

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

To verify:

$a(b-c)=ab-ac$ for the given values.

Solution:

We have,

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

We need to verify $a(b-c)=ab-ac$ .

Taking left hand side, we get

$a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)$

$a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)$

Taking LCM, we get

$a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)$

$a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)$

$a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)$

$a(b-c)=-\dfrac{68}{35}\right)$

Taking right hand side, we get

$ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}$

$ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}$

$ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}$

Taking LCM, we get

$ab-ac=\dfrac{-28-40}{35}$

$ab-ac=\dfrac{-68}{35}$

Now,

$LHS=RHS$

Hence proved.

7 0

2 years ago