Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
its not worth 25 points but ok here u go let's solve your equation step-by-step.
3y−1=13−4y
Step 1: Simplify both sides of the equation.
3y−1=13−4y
3y+−1=13+−4y
3y−1=−4y+13
Step 2: Add 4y to both sides.
3y−1+4y=−4y+13+4y
7y−1=13
Step 3: Add 1 to both sides.
7y−1+1=13+1
7y=14
Step 4: Divide both sides by 7.
7y
7
=
14
7
y=2
Answer:
y=2 so there your answer is this equation has one solution your welcome
Answer:
The ratio of the circumference of a circle to its diameter is approximately 3.14.
Answer:
30.5
Step-by-step explanation:
I calculated it it might be the answer
4/7 : 14
2 : 49
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