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3 years ago

Plz help me do this

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

Data set doesn't go to 17

Step-by-step explanation:

None of the numbers go to 17

pychu [463]3 years ago

3 0

Answer:

1st option. the data set doesn't GO to seventeen

Step-by-step explanation:

look at the number line. I always had trouble with this so I get where your coming from first, look at where the line is touching don't pay attention to the box yet because it's confusing the entire point of this line is to show you that there MAY have been 1 or two people who where at 0 for this data and 1 or two people who were at 15

the point here is that the bulk of the data was 11-14, but because there were less people down lower, the mean of the data is at 13, and the data is bigger (skewed) to the left.

making everything lekse true except for the first option.

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Find the equation of the line that passes through (1, -1) and is parallel to

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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$2x+y-3=0\implies y=\stackrel{\stackrel{m}{\downarrow }}{-2} x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{-2}(x-\stackrel{x_1}{1}) \\\\\\ y+1=-2x+2\implies y=-2x+1$

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2 years ago

Given: tangent to Circle O.<br><br> If m C = 57°, then m BDR =

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∠BCD = 57°
∴ ∠BDR = ∠BCD = 57° (angle that meets the chord and the tangent is equi-angular to the angle at the alternate segment)

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3 years ago

HURRYYYWhat is the value of the expression (5)3?

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5x6=25x5=125 (125) I think it’s correct

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2 years ago

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Help<br><br> Determine which equation is parallel to line jk and which is perpendicular to line jk.

alukav5142 [94]

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:

Two lines with slopes $m_1$ and $m_2$ are parallel when $m_1=m_2$ and are perpendicular when $m_1*m_2=-1$

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

$\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}$

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

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3 years ago

Miguel conducts a survey of 750 college students to see how many of them have a part-time job. His results show that 500 of the

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Miguel: 500 out of 750 students have part time jobs.

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Among the choices, Choice B could represent Kureshi's Data because it is not proportional to the data of Miguel.

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