Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The probability of the television passing the test is p = 0.95
The sample size is n = 10
Generally the comprehensive testing process for all essential functions follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as
=> ![P(X \le 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}]+ [^{10}C_{10} * {0.95}^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%7B0.95%7D%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \le 9) = [10 * 0.6302 * 0.05 ]+ [1 *0.5987 * 1 ]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B10%20%2A%20%200.6302%20%20%2A%200.05%20%5D%2B%20%5B1%20%2A0.5987%20%2A%201%20%5D%20)
=>
Answer:
7
Step-by-step explanation:
1) for '8'; '3'; and '10':
8/2+3+3=10
2) for '2'; '5' and '11':
2/1+5+5=11
3) for '6'; '2' and '?':
6/2+2+2=7
Answer:
Step-by-step explanation:
The standard form for the equation of a circle is 
where r is the radius, and the center is (h, k).
(h, k) = (-1, 2), r = 7
-4 is the correct answer. -24= -4/6
<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
