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VMariaS [17]
3 years ago
13

NO LINKS! NO FILES please :)

Mathematics
2 answers:
Schach [20]3 years ago
7 0
The answer is 40 from what I see
lorasvet [3.4K]3 years ago
5 0

Answer:

the answer is 40 because you count all the squares that are in the shape

Step-by-step explanation:

You might be interested in
Take a factor out of the square root:
Nat2105 [25]

Answer:

See below.

Step-by-step explanation:

Lets take √72:

Factoring 72 to find perfect squares:

72 = 2*2*2*3*3

The largest perfect square in the above = 2*2*3*3 = 36.

So we can write 72 as 36*2.

√72 = √(36 * 2)

√36 * √2

= 6√2.

One more example:

√18  = √(2*3*3)

= √9*√2

= 3√2.

6 0
3 years ago
HELPPPPPP MEEEEE<br><br> y=6x-1<br><br> and -2x-3y=-2 <br><br><br> USING SUBSTITUTION
bazaltina [42]
Answer:
 x = 4 
y =23 

work:
 plug in the value of Y to -2x-3y=-2. -2x - 3(<span>6x-1) = -2
 
multiply 3 and the numbers in parenthesis. -2x -18x - 3 =-2
combine like terms (-2x -18x). -20x - 3 = -2
subtract 3 from both sides to isolate the variable. -20x = -5 
divide to isolate the variable (-20/-5) x = 4
-
now that we know the value of x, it'll be easy to find Y.
Plug it in to the first equation.
</span><span>y=6(4)-1
</span>y = 24 - 1
y = 23

so x = 4 
and y = 23 

hope this helps! :D
7 0
3 years ago
2×2=<br><br> Have a nice night.
nydimaria [60]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Determine whether the following graph represents a function.
Nata [24]

Answer:

yes

Step-by-step explanation:

5 0
2 years ago
For the following exercises, solve each inequality and write the solution in interval notation.
Pie

Answer:

The solution of the given set in interval form is $(-\infty,-4] \cup[12, \infty)$.

Step-by-step explanation:

It is given in the question an inequality as $|x-4| \geq 8$.

It is required to determine the solution of the inequality.

To determine the solution of the inequality, solve the inequality $x-4 \geq 8$ and, $x-4 \leq-8$

Step 1 of 2

Solve the inequality $x-4 \geq 8$

$$\begin{aligned}&x-4 \geq 8 \\&x-4+4 \geq 8+4 \\&x \geq 12\end{aligned}$$

Solve the inequality $x-4 \leq-8$.

$$\begin{aligned}&x-4 \leq-8 \\&x-4+4 \leq-8+4 \\&x \leq-4\end{aligned}$$

Step 2 of 2

The common solution from the above two solutions is x less than -4 and $x \geq 12$.

The solution set in terms of interval is $(-\infty,-4] \cup[12, \infty)$.

7 0
2 years ago
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