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dybincka [34]
3 years ago
12

Will mark brainliest for correct answer!

Mathematics
1 answer:
Darya [45]3 years ago
8 0

Answer:

...............

Step-by-step explanation:

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Write each fraction or mixed number as the sum of fractions in two different ways 1 1/4 and 1 3/5
DENIUS [597]
1 1/4 = 5/4 

1 3/5=  8/5
8 0
3 years ago
Compute the standard deviation of the following set of data to the nearest whole number:
Klio2033 [76]

Answer:

Step-by-step explanation:

The standard deviation is the square root of the variance, and the variance is found by using the mean. So we will do that first. I will use the population variance as opposed to the sample variance since our set of numbers is small.

The mean: 8 + 12 + 15 + 17 + 18 = 70 and divide that by 5 to get

\bar{x}=14 and use this to find the variance in the formula:

s^2=\frac{\sum(x_i-\bar{x})^2}{n} it is a bit difficult to enter that formula in correctly, but here's how it works mathematically:

s^2=\frac{(8-14)^2+(12-14)^2+(15-14)^2+(17-14)^2+(18-14)^2}{5}

Squaring this ensures us that we don't end up with zero, which would be useless.

s^2=\frac{36+4+1+9+16}{5} so

s^2=13.2 which means that the standard deviation is

s = 3.633

(If you do it with n-1 = 4 in the denominator of the variance, you get a standard deviation of 4.062)

3 0
3 years ago
HELP ASAP!!!!<br> Given (x, y ) = (5, 15). Find tan θ.
Darina [25.2K]
<span>tan θ is defined as the opposite/adjacent side to the angle in a triangle

in this case you have a triangle which forms from (0,0) to (5,0) and (5,15), with </span><span>θ at (0,0)

-> your x coordinate is the adjacent side, and y the opposite
</span>
<span>tan θ=opposite/adjacent=y/x=15/5=3</span>
8 0
4 years ago
In the equation Y+8=2 what does y=?
Jet001 [13]
Y = -6 hope this helps
5 0
3 years ago
Leave answer in the simplest radical form.
slega [8]

\cfrac{7x^{-\frac{3}{2}} ~~ y^{\frac{5}{2}} ~~ z^{-\frac{2}{3}}}{56 x^{-\frac{1}{2}} ~~ y^{\frac{1}{4}}}\implies \cfrac{7}{56}\cdot \cfrac{y^{\frac{5}{2}} ~~ y^{-\frac{1}{4}}}{x^{-\frac{1}{2}} ~~ x^{\frac{3}{2}} ~~ z^{\frac{2}{3}}}\implies \cfrac{1}{8}\cfrac{y^{\frac{5}{2}-\frac{1}{4}}}{x^{-\frac{1}{2}+\frac{3}{2}}~~ z^{\frac{2}{3}}}

\cfrac{y^{\frac{9}{4}}}{8x z^{\frac{2}{3}}}\implies \cfrac{\sqrt[4]{y^9}}{8x\sqrt[3]{z^2}}\implies \cfrac{\sqrt[4]{y (y^2)^4}}{8x\sqrt[3]{z^2}}\implies \cfrac{y^2 \sqrt[4]{y}}{8x\sqrt[3]{z^2}}

7 0
2 years ago
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