All categories

3 years ago

Please help I hate math

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

4 0

Answer:

the first fraction is 9 and the second one is -5

Step-by-step explanation:

devlian [24]3 years ago

3 0

Answer:

3/5=9/15

-1/3= -5/15

Step-by-step explanation:

You might be interested in

Analyze the end behavior of each function below. Then, choose one of the functions, and explain how you determined

kumpel [21]

Answer:

End behavior of a polynomial function depended on the degree and its leading coefficient.

1. If degree is even and leading coefficient is positive then

$p(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

2. If degree is even and leading coefficient is negative then

$p(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

3. If degree is odd and leading coefficient is positive then

$p(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

4. If degree is odd and leading coefficient is negative then

$p(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

(a)

$f(x)=x^4$

Here, degree is even and leading coefficient is positive.

$f(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$f(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

(b)

$g(x)=-x^4$

Here, degree is even and leading coefficient is negative.

$g(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$g(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

(c)

$h(x)=x^3$

Here, degree is odd and leading coefficient is positive.

$h(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$h(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

(d)

$k(x)=-x^3$

Here, degree is odd and leading coefficient is negative.

$k(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$k(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

4 0

3 years ago

Find the 10th term if a1=1531 and d=76.

xz_007 [3.2K]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ n= 10\\ a_1=1531\\ d=76 \end{cases} \\\\\\ a_{10}=1531+(10-1)76\implies a_{10}=1531+(9)76\implies a_{10}=1531+684 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill a_{10}=2215~\hfill$

5 0

3 years ago

Leveled

Marat540 [252]

Answer:

48.6

Step-by-step explanation:

Put the values in place of the variables and simplify according to the Order of Operations in the usual way.

10.2x +9.4y

= 10.2(2) +9.4(3) . . . . . 2 is substituted for x; 3 is substituted for y

= 20.4 +28.2

= 48.6

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=5%20-%205%20%5Ctimes%202%20%2B%2011" id="TexFormula1" title="5 - 5 \times 2 + 11" alt="5 - 5 \

Rasek [7]

Answer:

Step-by-step explanation:

We use BODMAS/BIDMAS here.

First, we do 5 × 2, as multiplication comes before subtracting and adding.

5 × 2 = 10

Now we can just add and subtract.

5 - 10 = -5

-5 + 11 = 6

3 0

3 years ago

Plz help i only need this question who ever get its right will get 77 point

Ivanshal [37]

Answer:

I don't know..............

8 0

3 years ago

Read 2 more answers