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qaws [65]
3 years ago
13

1. Find the value of sec Θ if tan Θ = -2 90° ≤ Θ ≤ 180°

Mathematics
1 answer:
blondinia [14]3 years ago
3 0

9514 1404 393

Answer:

  1. (a) -√5

  2. 3/5

Step-by-step explanation:

1. sec²(θ) = tan²(θ) +1

  sec²(θ) = (-2)² + 1 = 5

  sec(θ) = ±√5

In the second quadrant, secant is negative, so ...

  sec(θ) = -√5

__

2. cos(θ) = 1/sec(θ)

  cos(θ) = 1/(5/3)

  cos(θ) = 3/5

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29. Fifty percent of the parallelogram is shaded. What is the area of the shaded region?
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Answer:

25 cm

Step-by-step explanation:

the whole parallelograph is 5 times 10 which equals 50. Devide that by 2 and you get 25

5 0
3 years ago
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Anyone help?<br><br> What is the derivative of x^2 + 2x - 4?<br><br> Thanks!
castortr0y [4]
Let's take the derivative of each term one by 1

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Apply the power rule for derivatives.
2x^(2-1) = 2x
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2x
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2 * x^(1-1) = 2 * x^0 = 2
You get 2.

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3 years ago
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What are interest rates? Please explain.
Dmitry_Shevchenko [17]

Answer:

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3 0
3 years ago
PLEASE HELP, BEEN STUCK FOR AN HOUR
djverab [1.8K]

Answer:

Step-by-step explanation:

To sketch a quadratic function we need two things:

1)  Nature of the curve

2) Vertex

3) y-intercept

The completing square form of the quadratic equation is:

y=a(x-h)^2+k

where,

a represents the nature of the graph it can be maximum or minimum , meaning, if a > 0 then minimum(u shaped curve/happy face) and if a < 0 then maximum(n shaped curve/sad face).

h represents the x-coordinate of the vertex.

k represents the y-coordinate of the vertex.

Now if we compare g(x) with our completing square form we get the following:

g(x)=(x-4)^2+12\\y=a(x-h)^2+k\\

When we simply compare the following we get ,

a = 1 , which means a > 0 since 1 is greater than 0 the nature of the curve will be minimum(happy face/u shaped)

h = 4, which means the x-coordinate of the vertex is 4

k = 12, which means the y-coordinate of the vertex is 12

Now we have the nature of the curve, we have the vertex now all we need is the y-intercept.

For y-intercept:

For y-intercept meaning at which point will the graph cross the y-axis(0 , y)

For that we expand the formula and turn it into the standard quadratic equation form by using the formula (a - b)^2

y=(x-4)^2+12\\y=((x)^2-2(x)(4)+(4)^2)+12\\y=x^2-8x+16+12\\y=x^2-8x+28\\

now we compare with the standard quadratic form:

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here c is the y-intercept and while comparing we can see that c = 28 ,

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So we have all the three things that we need to graph our function.

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3 years ago
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