Fine but I ain't showing my work completely.
The sum of all ext. angles of a polygon = 360.
So, you make this formula and solve for x.
360 = 49 + (3x+30) + (14x+6) + (6x-3) + (4x+8)
360 = 49 + 27x + 30 + 6 -3 + 8
360 = 90 + 27x
270 = 27x
/27 /27
10 = x
Now substitute for angle A, which is (6x-3)
6x-3
6(10)-3
60-3
57
Therefore, angle A is 57 degrees.
Answer:
Solution given:
now
f(x)+g(x)=
....(1)
now
factoring x²+6x-40
we get
x²+10x-4x-40
x(x+10)-4(x+10)
(x+10)(x-4)
now substituting in equation 1 ,we get
f(x)+g(x)=
taking l.c.m
=
=now
opening bracket
=
So
answer is :
B. 
C cubed minus the product of five and Q +4
=
C^3 - [5(Q +4)]
Question is a bit vague. If you wish to graph this inequality, you'll need to know what the graph of the absolute value function y = |x| looks like; it's a " V " with the vertex at the origin. The slope of the right half of the graph is m=1. Draw this function.
Next, subtract 2 from both sides. We'll get <span> |x + 1| < –1 - 2
or
</span> |x + 1| < –3. We can stop here! Why! because the absolute value function is never smaller than zero, and so <span> |x + 1| is never smaller than -3.
You could, of course, graph y = |x+1|; start with your graph for y = |x| and then move the whole graph 1 unit to the left (away from the origin). If you do this properly you'll see that the entire graph is above the x-axis, except for the vertex (-1,0). Again, that tells us that the given inequality has no solution.
</span>
Answer:
Step-by-step explanation:
