Hi guys I really need the answer for this one pls don’t disappoint me I really need this because is for a test

Marley and her friends by three types of popcorn at the movies $40 each and some candy that cost seven dollars. If the girls spe

drek231 [11]

Answer: they bought 2 things of candy 7 dollars each and one tub of popcorn costing 14 dollars but the most that it could cost is 21 dollars

Step-by-step explanation:

3 0

3 years ago

The amount of water in a bottle is approximately normally distributed with a mean of 2.55 liters with a standard deviation of 0.

Natalka [10]

Answer:

a) $P(X$

b) $P(\bar X$

c) $P(\bar X$

d) For part a we are just finding the probability that an individual bottle would have a value of 2.52 liters or less. So we can't compare the result of part a with the results for parts b and c.

If we see part b and c are similar but the difference it's on the sample size for part b we just have a sample size 4 and for part c we have a sample size of 25. The differences are because we have a higher standard error for part b compared to part c.

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Let X the random variable that represent the amount of water in a bottle of a population, and for this case we know the distribution for X is given by:

$X \sim N(2.55,0.035)$

a. What is the probability that an individual bottle contains less than 2.52 liters?

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(X$

b. If a sample of 4 bottles is selected, what is the probability that the sample mean amount contained is less than 2.52 liters? (Round to three decimal places as noeded)

And let $\bar X$ represent the sample mean, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

On this case $\bar X \sim N(2.55,\frac{0.035}{\sqrt{4}})$

The z score on this case is given by this formula:

$z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we replace the values that we have we got:

$z=\frac{2.52-2.55}{\frac{0.035}{\sqrt{4}}}=-1.714$

For this case we can use a table or excel to find the probability required:

$P(\bar X$

c. If a sample of 25 bottles is selected, what is the probability that the sample mean amount contained is less than 2.52 liters? (Round to three decimal places as needed.)

The z score on this case is given by this formula:

$z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we replace the values that we have we got:

$z=\frac{2.52-2.55}{\frac{0.035}{\sqrt{25}}}=-4.286$

For this case we can use a table or excel to find the probability required:

$P(\bar X$

d. Explain the difference in the results of (a) and (c)

For part a we are just finding the probability that an individual bottle would have a value of 2.52 liters or less. So we can't compare the result of part a with the results for parts b and c.

If we see part b and c are similar but the difference it's on the sample size for part b we just have a sample size 4 and for part c we have a sample size of 25. The differences are because we have a higher standard error for part b compared to part c.

3 0

3 years ago

The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is form

pantera1 [17]

If you're going to use technology (Brainly), you may as well use appropriate technology (a triangle solver). Many graphing calculators have this function built in.

a ≈ 5.82
A ≈ 21.2°
C ≈ 21.8°

Since the longest side (b) is opposite the given angle (B), the triangle has one solution.
.. C = arcsin(6/11*sin(137°))
.. A = 180° -137° -C
.. a = sin(A)*11/sin(137°)