They are called unike fractions. If u would want to do anything to them u would have to make the denominaters the same
The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=
(-4)=-8/(
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+

=-2+2(x+4)/1!-24/16
/2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16
/2!+...........
Learn more about taylor series at brainly.com/question/23334489
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4/5x + 4/3 = 2x....there are 2 ways to do this...one with fractions, one without.
with :
4/5x + 4/3 = 2x
4/3 = 2x - 4/5x
4/3 = 10/5x - 4/5x
4/3 = 6/5x
4/3 * 5/6 = x
20/18 = x
10/9 = x
without :
4/5x + 4/3 = 2x....multiply by common denominator of 15
12x + 20 = 30x
20 = 30x - 12x
20 = 18x
20/18 = x
10/9 = x
This is a weird question but I believe sense you did bring the money then you are going to buy lunch.
Answer:
with what lol?
Step-by-step explanation: