Answer:
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10)=(-3)^2.x^4×2.y^2(5.x^2y^6)-7^2x^5×2y^4×2
=(9×5)x^8+2y^2+6-49x^10y^8
=45x^8+2y^2+6-49x^10y^8
=45x^10y^8-49x^10y^8
=-4x^10y^8
173
____
4)692
4
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29
28
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12
12
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0
2(a+bc)=2a+2bc
3.(ab-cb-ba+bc)= 3ab-3cb-3ba+3bc
Since the brackets and multiplication have a higher order than the rest.
Cb=Bc
Ab=ba
Ac=Ca
Because multiplication is commutative.
2a+2bc + cb +ab + ac -(3ab-3cb-3ba+3bc)
2a + 2bc + cb + ab + ac(+ -3ab - - 3cb - -3ba +-3bc)
2a + 2bc + cb + ab + ac -3ab + 3cb + 3ba -3bc
2a + (2bc-3bc +cb + 3cb ) + (ab -3ab + 3ba) + ac
=2a + 3cb + ba+ ac OR 2a +3bc + ab + ac
The Or is just a different way to write it.
Hope this helps
The complete question is
Which statement is true about the factorization of 30x² + 40xy + 51y²<span>?
A. The factorization of the polynomial is 10(3x2 + 4xy + 5y2).
B. The polynomial can be rewritten as the product of a trinomial and xy.
C. The greatest common factor of the polynomial is 51x2y2.
D. The polynomial is prime, and the greatest common factor of the terms is 1.
we know that
case A) </span>is not right because 10 is not a common factor of the three terms.
case B) is not right because the original polynomial is already a trinomial
case C) is not right because the terms do not contain 51x^2y^2
<span>case D) is right
because
</span><span>Factors of 30 are-----> 1,2,3,5,6,10,15,30
</span>Factors of 40 are-----> 1,2,4,5,8,10,20,40
Factors of 51 are-----> 1,51
<span>so
</span><span>The "Greatest Common Factor" is the largest of the common factors
</span><span>the GFC is 1
therefore
the answer is the option
</span>D. The polynomial is prime, and the greatest common factor of the terms is 1<span>
</span>
The answer is B. Hope it helped
