So in order to find line AC you must find line AD and DC then plus them together.
to find AD use Pythagoras theorem
a^2 = c^2 - b^2
AD^2 = 7.5^2 - 6.5^2
AD^2 = 56.25 - 42.25
AD^2 = 14
square root both sides to get rid of the ^2
AD ≈ 3.7 or 3.74
Do the same for DC
DC^2 = 10^2 - 6.5^2
DC^2 = 100 - 42.25
DC^2 = 57.75
DC ≈ 7.6
now plus AD and DC which should give u 11.3
Answer:
The Answer is that Senior Citizen Tickets cost: $4 and Child tickets cost: $7.
Step-by-step explanation:
Let s = the cost of senior citizen tickets
Let c = the cost of child tickets
The number of tickets sold for each type added together equals the sales for each day. Equations below:
Day 1
3s + 9c = $75
Solve for s:
3s = 75 - 9c
s = 25 - 3c
Day 2
8s + 5c = $67
By substitution:
8(25 - 3c) + 5c = 67
200 - 24c + 5c = 67
-19c = -133
c = -133 / -19 = $7 cost for child tickets.
Solve for s:
s = 25 - 3c
s = 25 - 3(7)
s = 25 - 21 = $4 cost for senior citizen tickets.
Proofs:
Day 1
3s + 9c = $75
3(4) + 9(7) = 75
12 + 63 = 75
75 = 75
Day 2
8s + 5c = $67
8(4) + 5(7) = 67
32 + 35 = 67
67 = 67
The fourth one I think hope it helps
8(10-K) = 2k
mutiply the bracket by 8
(8)(10)= 80
(8)(-k)= -8k
80-8k= 2k
move -8k to the other side
sign changes from -8k to +8k
80-8k+8k= 2k+8k
80= 2k+8k
80= 10k
divide by 10 for both sides
80/10= 10k/10
k= 8
Answer: k= 8
