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dimulka [17.4K]
3 years ago
10

which of these statement correctly compares the graphed the functions g(x) to the function g(x)=-x/2+5

Mathematics
1 answer:
nordsb [41]3 years ago
7 0

Answer: A. The rate of change of f(x) is 1/2.

Step-by-step explanation:

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How do i do disss pls help​
masya89 [10]
Number one would be x=4, I hope this helps
8 0
3 years ago
What is the probability of randomly drawing an odd number between 24 and 33?
Studentka2010 [4]
Write out the numbers between 24 and 33:  {24, 25, 26, 27, 28, 29, 30, 31, 32, 33}

How many numbers have we here?  10.

How many of these numbers are odd?  {25, 27, 29, 31, 33}

Strictly speaking, "between 24 and 33" does not include {24, 33}.

Thus, the odd numbers between 24 and 33 are {25, 27, 29, 31}

The chances of drawing an odd number between 24 and 33 are then 4 / 10.

If, however, we omit the endpoints 24 and 33, then there are 8 numbers between 24 and 33:  {25, 27, 29, 31}

and the odds of choosing an odd number from these eight numbers is 4/8, or 1/2, or 0.50.
6 0
3 years ago
Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0
mixas84 [53]

The equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

We rewrite the equation and set them equal :

$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0

$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

#SPJ4

7 0
1 year ago
Which values of k are solutions to the inequality StartAbsoluteValue negative k minus 2 EndAbsoluteValue less-than 18? Check all
Stella [2.4K]

Answer:

You could just replace all the given possible values of k in the inequality and see which ones are solutions, but let's solve this in a more interesting way:

First, remember how the absolute value works:

IxI = x if x ≥ 0

IxI = -x if x ≤ 0

Then if we have something like:

IxI < B

We can rewrite this as

-B < x < B

Now let's answer the question, here we have the inequality:

I-k -2I < 18

Then we can rewrite this as:

-18 < (-k - 2) < 18

Now let's isolate k:

first, we can add 2 in the 3 parts of the inequality:

-18 + 2 < -k - 2 + 2 < 18 + 2

-16 < -k < 20

Now we can multiply all sides by -1, remember that this also changes the direction of the signs, then:

-1*-16 > -1*-k > -1*20

16 > k > -20

Then k can be any value between these two limits.

So the correct options (from the given ones) are:

k = -16

k = -8

k = 0

6 0
2 years ago
Read 2 more answers
Solve the equation 3x-1=x+9
Sever21 [200]
5.

3x - 1 = x + 9

Subtract x on both sides

2x - 1 = 9

Add one on both sides.

2x = 10

Divide by 2 to get the x.

x = 5

Hope this helps!
5 0
3 years ago
Read 2 more answers
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