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2 years ago

What is the probability of not rolling factors of 3 on both dice

Mathematics

1 answer:

ruslelena [56]2 years ago

5 0

Answer:

So basically if there's 6 numbers on each dice, that means that there's a 5/6 chance of not getting a 3. So multiply that and you get 5/6*5/6. That is equal to 25/36 change.

<h2><u>Answer: 25/36 chance or about 69.4444...%</u></h2>

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Answer:

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Step-by-step explanation:

Given

$(\frac{b}{r})^2 + (\frac{a}{r})^2$

Required

Use the expression to prove a trigonometry identity

The given expression is not complete until it is written as:

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = (\frac{r}{r})^2$

Going by the Pythagoras theorem, we can assume the following.

a = Opposite
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So, we have:

$Sin\theta = \frac{a}{r}$

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Having said that:

The expression can be further simplified as:

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1$

Substitute values for sin and cos

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1$ becomes

$cos^2\theta + sin^2\theta = 1$

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3 years ago

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Dmitry [639]

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Answer:

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Step-by-step explanation:

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