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3 years ago

What is the probability of not rolling factors of 3 on both dice

Mathematics

1 answer:

ruslelena [56]3 years ago

5 0

Answer:

So basically if there's 6 numbers on each dice, that means that there's a 5/6 chance of not getting a 3. So multiply that and you get 5/6*5/6. That is equal to 25/36 change.

<h2><u>Answer: 25/36 chance or about 69.4444...%</u></h2>

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The larger of two numbers is 33 more than the smaller. When added together, the sum of the larger number and five times the smal

VARVARA [1.3K]

Step-by-step explanation:

let the larger number be x and smaller number be y

according to this question

x=y+33----------(1)

y+33+5y=129----------(2)

6y+33=129

y=16

x=16+33(takimg equation (1)

x=49

4 0

3 years ago

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gogolik [260]

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2 years ago

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Its length is

melamori03 [73]

Answer:

$100

Step-by-step explanation:

40x30=1200

1200/12=100

7 0

3 years ago

Help me with this please.

dusya [7]

2.5 *(10)+15=40
I guess this is the answer :)

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3 years ago

The mean length of 4 childrens' big finger is 14cm. The mean length of 9 adults' big finger is 16.1cm. What is the mean length (

Mamont248 [21]

Answer:

The mean length of the 13 people's big finger is 15.45 cm

Step-by-step explanation:

Given;

mean length of 4 childrens' big finger, x' = 14cm

mean length of 9 adults' big finger is 16.1cm, x'' = 16.1cm

Let the total length of the 4 childrens' big finger = t

$x' = \frac{t}{n} \\\\x' = \frac{t}{4}\\\\t = 4x'\\\\t = 4 *14\\\\t = 56 \ cm$

Let the total length of the 9 adults' big finger = T

$x'' = \frac{T}{N} \\\\x'' = \frac{T}{9}\\\\T = 9x''\\\\T = 9*16.1\\\\T = 144.9 \ cm$

The total length of the 13 people's big finger = t + T

= 56 + 144.9

=200.9 cm

The mean length of these 13 people's big finger;

x''' = (200.9) / 13

x''' = 15.4539 cm

x''' = 15.45 cm (2 DP)

Therefore, the mean length of the 13 people's big finger is 15.45 cm

3 0

3 years ago