In slope intercept form its, y=2x-2
Answer:
48 + 12√3 units
Step-by-step explanation:
ALL LENGTHS MUST BE POSITIVE (I did this to avoid writing ± and showing that only + works)
1. Find AD (you'll find why later): 15² = 9² + AD² --> AD² = 144 --> AD = 12
2. 30-60-90: 12-DC-AC --> AC = 24, DC = 12√3 (side opposite of 90 is double side opposite of 30, side opposite of 60 is √3 times the opposite of 30)
P = AB + BD + DC + AC = 15 + 9 + 12√3 + 24 = 48 + 12√3 units
Answer:
C. None of the above
Step-by-step explanation:
we know that
The number of students who signed up for different after school activities are
Cooking------------> 9 students
Chess---------------> 4 students
Photography-----> 8 students
Robotics-----------> 11 students
Total of students -----> (9+4+8+11)=32
<u><em>Verify each statement</em></u>
case A) The ratio of photography students to all is 4:1
The statement is false
Because the ratio of photography students to all is 8:32
Simplify
1:4
case B) For every 1 chess student there are a total of 16 students
The statement is false
Because the ratio of chess student to all is 4:32
Simplify
1:8
so
For every 1 chess student there are a total of 8 students
therefore
C. None of the above
What? That’s not possible because there’s no blue pens. If that’s the awnser?
Say we add 5 to each element. We sum them up and divide by the number of elements (compute mean). Well we added 5n to that total sum and are dividing by n. So if the mean was 10 before, now it’s 15. (We had 10 datapoints added too 100, but we added 50, dividing by 10 we get 15).
Now every single data point is just as close to the mean as it was before. The mean shifted with 5, but so did the datapoints. Remember, variance is the sum of squared errors divided by n, or n-1 for sample. Well, the sum of squared errors did not change. So our estimate of variance remains the same as well as our estimate of standard deviation.
This is without assuming normality. (ie through the equation of mean and standard deviation themselves). In general expected values shift with constants, and variances remain stable.
