<h3><u>Answer;</u></h3>
= 49.42 g
<h3><u>Explanation;</u></h3>
The equation for the reaction between Lead (ii) nitrate and sodium iodide;
Pb(NO3)2(aq) + 2 NaI(aq) ---> 2NaNO3(aq) + PbI2(s)
The precipitate formed in this equation is Lead iodide
We first calculate the moles of lead nitrate;
Moles = mass/molar mass
= 35.5 g/ 331.2 g/mol
= 0.1072 moles
The mole ratio of Pb(NO3)2 : PbI2 is 1 : 1
Therefore; the number of moles of lead iodide is 0.1072 moles
Mass = moles × molar mass
= 0.1072 moles × 461.01 g/mol
<u>= 49.42 g</u>
Water is the answer because the word <span>Hydroelectric has hydro in it and hydro= water.</span>
They are classified by similar properties and number of valence electrons and energy levels
Answer:
Potassium dihydrogen phosphate is a potassium salt in which dihydrogen phosphate(1-) is the counterion. ... It is a source of phosphorus and potassium as well as a buffering agent. It can be used in fertilizer mixtures to reduce escape of ammonia by keeping pH low.
Explanation:
