Answer:
Dissociation factor = 1.8
Explanation:
Data provided in the question:
Molecular weight of the Procaine hydrochloride = 273
Number of ions contained, n = 2
Fraction Dissociating, α = 80% = 0.8
Now,
the dissociation factor 'i' is given as:
i = 1 + α × ( n - 1 )
on substituting the respective values, we get
i = 1 + 0.8 × ( 2 - 1 )
or
i = 1 + ( 0.8 × 1 )
or
i = 1.8
Answer:
1 mole of any ideal gas occupies the same volume as one mole of any other ideal gas under the same conditions of temperature and pressure.So 1 L CO2 has same number of moles as 1 L O2 and 1 L N2 etc.This means that, assuming all the gases in air are ideal gases, if CO2 is 4.0 % by volume then it is also 4.0 % by moles, because a volume of each gas has the same number of moles.
Explanation:
Answer;
A decrease in the vapor pressure of the liquid.
Dissolving a solute such as potassium hydroxide in a solvent such as water results in a decrease in the vapor pressure of the liquid.
Explanation;
The vapor pressure of a liquid is the equilibrium of a vapor above its liquid.
In other words it is the pressure of the vapor resulting from the evaporation of a liquid above a given sample of the liquid in a closed container.
The vapor pressure of a liquid in a closed container depends on the temperature.
I think it's 11.56 minutes
Answer:
Pyridine solution has a greater concentration of hydroxide ions.
Explanation:
The pOH of the solution is defined as negative logarithm of hydroxide ion concentration in a solution.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
- Higher the value of pOH lessor will be the hydroxide ion concentration and higher the concentration of hydrogen ions in the solution .
- Lower the value of pOH higher will be the hydroxide ion concentration and lower the concentration of hydrogen ions in the solution.
1) The pOH of the methylamine = 6.8
![6.8=-\log[OH^-]](https://tex.z-dn.net/?f=6.8%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=1.5848\times 10^{-7} M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.5848%5Ctimes%2010%5E%7B-7%7D%20M)
2) The pOH of the pyridine = 6.0
![6.0=-\log[OH^-]](https://tex.z-dn.net/?f=6.0%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=0.000001 M=1.0\times 10^{-6} M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.000001%20M%3D1.0%5Ctimes%2010%5E%7B-6%7D%20M)
Pyridine solution has a greater concentration of hydroxide ions than the solution of methylamine.