HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> Show your work

I need help with question c

Lyrx [107]

Answer:

take the common between dy and y

do similarly also with x .and make a equation

3 0

2 years ago

LOOK AT THE PICTURE ATTACHED FOR THE QUESTION GIVING OUT EXTRA POINTS IF THE ANSWER IS RIGHT!!!!

disa [49]

Answer:

$-4x^5y^3-3x^4y^3+x^5y^2$

Step-by-step explanation:

You need to know this indice rule:

If you multiply two terms with the same base, then add their powers and multiply their coefficients.

$(4x^2y+3xy-x^2)(-x^3y^2)$ : Here we have to multiply each term in the first pair of brackets by the term in the second pair of brackets.

So we can split this into parts:

$(4x^2y)(-x^3y^2) +(3xy)(-x^3y^2)+(-x^2)(-x^3y^2)$

Now using the rule above expand the brackets:

$(4x^2y)(-x^3y^2) = -4x^5y^3$ : Notice how $y * y^2 =y^3$ since $y$ $= y^1$ so $1 + 2 = 3$ .

$(3xy)(-x^3y^2) = -3x^4y^3$

$(-x^2)(-x^3y^2)$ $= x^5y^2$ : Be careful with negatives, two negatives make a positive.

Now add them all together:

$-4x^5y^3-3x^4y^3+x^5y^2$

6 0

3 years ago

Suppose that a researcher is planning a new study on hemoglobin levels amongst women under 25 years old. Previous research sugge

Mariulka [41]

Answer:

A sample size of at least 531 is required.

Step-by-step explanation:

We are lacking the confidence level to solve this question, so i am going to use a 90% confidence level.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Find the required sample size for the new study.

A sample size of at least n is required.

n is found when $M = 0.05$

We have that $\sigma = 0.7$

So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.645*\frac{0.7}{\sqrt{n}}$

$0.05\sqrt{n} = 1.645*0.7$

$\sqrt{n} = \frac{1.645*0.7}{0.05}$

$(\sqrt{n})^{2} = (\frac{1.645*0.7}{0.05})^{2}$

$n = 530.4$

Rounding up

A sample size of at least 531 is required.

5 0

3 years ago

Help help help pls pls pls

alex41 [277]

Answer: 14.48000 . . . ≤ t < 15.0000

Step-by-step explanation:

"Truncated by a hundreths of a second" means that the time was rounded to the nearest 0.0X second. That would mean the reported time of 14.48 seconds was shortened from a time period having more digits to the right. For example, If the time were actually 14.48223 seconds, the time was truncated to just 14.48 seconds. The term used here. truncated, means that the digits after the hunredth place are simply dropped. It doesn't say rounded, just truncated. Brutal. So that would mean that times between 14.48000 . . . and 14.48999 . . . would all be reported as 14.48 seconds.

So the time could actually be 14.48000 . . . ≤ t < 15.0000

3 0

3 years ago

2 Find the mystery numbers for each pair of clues. A product is the number you get

balu736 [363]

Answer:

4 and 3 at least i think

Step-by-step explanation:

5 0

3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!! Show your work