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kolbaska11 [484]
3 years ago
11

PLEASE HELP FAST!! Giving all my points. And will mark brainliest

Mathematics
2 answers:
Finger [1]3 years ago
4 0

The 1/2 will change all values of f(x) to 1/2 f(x) so the graph of  f(x) will shrink vertically  by a factor of 1/2.

The third option is the correct one.

nydimaria [60]3 years ago
4 0

f(x) vs (a)(f(x))

if a<0, that is known as a vertical compresion


our 1st 3 option show a vertical compression

since a<0, it will shrink vertically by a factor o 1/2


last option, hmm, range is height or y value

by subtracting 2, you move it in the x direction so no change in range from that

however, vertically compressing it makes the y values smallers so range is different


answer is only the 3rd option, shrink vertically

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Please help. Will give brainliest! No links or your account will be a banned
Firdavs [7]

Answer:

1. 18

2. -8

3. 1

4. 84

Step-by-step explanation:

hope this helps! :D

have a miraculous day, and brainliest is immensely appreciated!! <3

5 0
2 years ago
How do you find the area of this composite figure?
Illusion [34]
If you notice the picture below

the composite figure is just a trapezoid sitting on top of a rectangle
and then, the rectangle has a triangular hole in it

so.. get the area of the trapezoid   \bf \textit{area of a trapezoid}=A=\cfrac{h}{2}(a+b)\qquad &#10;\begin{cases}&#10;h=height\\&#10;a,b=\textit{parallel sides or bases}&#10;\end{cases}

then get the area of the rectangle, which is just a 12x14
and then get the area of the triangle, which surely you know is 1/2 bh

then, subtract the triangle's area from the rectangle's area

and whatever is left, namely the difference, add that to the area of the trapezoid, and that's the composite's area

namely the area of the trapezoid plus the rectangle's, minus the triangle's

6 0
3 years ago
Find the area of the circle below
tangare [24]

Answer:

28.27433

Step-by-step explanation:

using the pie radius squared formula

pie radius squared=pie 3 squared

5 0
3 years ago
Read 2 more answers
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

6 0
3 years ago
. A tennis supply store pays a wholesaler $90 for a tennis racquet and sells it for $144. What is the markup rate?
I am Lyosha [343]


Formula : Amount of change / Original amount

             1.      144 - 90/ 144

             2.      Subtract 144 and 90

             3.      54/ 144

             4.      Divide 54 by 144

             5       0.375

             6       Move the decimal two places to the right.

              7.      37.5 %

Answer: 37.5% is the markup rate

6 0
3 years ago
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