Suppose 56%of politicians are lawyers.If a random sample of size 564 is selected, what is the probability that the proportion of
1 answer:
Answer: 0.9444
Step-by-step explanation:
Given: The proportion of politicians are lawyers : <em>p </em>=0.56
Sample size : n = 564
Let q be th sample proportion.
The probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by greater than 4% will be :-
Hence, the required probability = 0.9444
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The answer to the question is a) -4.
Answer:
(x, y) = (1, ±2)
Step-by-step explanation:
To solve this pair of equations, one can add the second equation to twice the first:
2(2x +y^2) +(3x -2y^2) = 2(6) +(-5)
4x +3x = 12 -5 . . . . simplify a bit
7x = 7 . . . . . . . . . . . collect terms
x = 1 . . . . . . . . . . . . divide by 7
Then y can be found from the first equation:
y^2 = 6 -2x = 6 -2(1) = 4
y = ±√4 = ±2
The solutions are ...
(x, y) = (1, -2) or (1, 2)
