Suppose 56%of politicians are lawyers.If a random sample of size 564 is selected, what is the probability that the proportion of
1 answer:
Answer: 0.9444
Step-by-step explanation:
Given: The proportion of politicians are lawyers : <em>p </em>=0.56
Sample size : n = 564
Let q be th sample proportion.
The probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by greater than 4% will be :-
Hence, the required probability = 0.9444
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That’s the answer for this problem
The complete question in the attached figure
we have that
f(x) = x²<span> + 1
g(x) = x – 4
step 1
find </span>(f o g)(x)
(f o g)(x)= (x - 4)² + 1(f o g)(x) = x² - 8x + 16 + 1
(f o g)(x) = x² - 8x + 17
step 2
find (f o g)(10)
(f o g)(10) = 10² - 8*(10) + 17
(f o g)(10 = 100 - 80 + 17
(f o g)(10)= 37
the answer is 37
we have that
f(x) = x²<span> + 1
g(x) = x – 4
step 1
find </span>(f o g)(x)
(f o g)(x)= (x - 4)² + 1(f o g)(x) = x² - 8x + 16 + 1
(f o g)(x) = x² - 8x + 17
step 2
find (f o g)(10)
(f o g)(10) = 10² - 8*(10) + 17
(f o g)(10 = 100 - 80 + 17
(f o g)(10)= 37
the answer is 37