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Tomtit [17]
3 years ago
10

Subtract. Your answer should be a polynomial in standard form. (-9g^4+3g^2h+1) -(6g^4-3g^2h+h)

Mathematics
1 answer:
enyata [817]3 years ago
7 0
Just combine like terms and you get -15g^4+6g^2h-h+1
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3 years ago
Solve help please, thanks.
natka813 [3]

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3 years ago
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You may need to use the appropriate technology to answer this question. A survey was conducted to determine whether hours of sle
Marina CMI [18]

Answer:

1) The null and alternative hypotheses.

H0: Hours of sleep per night is independent of age.

Ha: Hours of sleep per night is not independent of age.

Test Statistics χ²=4.009

The corresponding p-value for the test at χ²= 4.009 is 0.2604

Step-by-step explanation:

1) The null and alternative hypotheses.

H0: Hours of sleep per night is independent of age.

Ha: Hours of sleep per night is not independent of age.

2) The data is

                              ≤ 39           ≥ 40              Total

6 hours                    36               34                70

6.9-7 hours              60              57               117

7- 7.9 hours              79              77               156

<u>8 hours or more       65              92              157</u>

<u>Total                       240           260             500</u>

<u />

3) The expected values are computed as follows

260×70/500=36.4

240×117/500 =56.16

260×117/500 =60.84

240×156/500 =74.88

260×156/500 =81.12

240×157/500=75.36

260×157/500 =81.64

4) The squared distances are calculated as

{(36 - 33.6)^2}/{ 33.6} = 0.171

{(34 - 36.4)^2}{ 36.4} = 0.158

{(60 - 56.16)^2}/{ 56.16} = 0.263

{(57 - 60.84)^2}/{ 60.84} = 0.242

{(79 - 74.88)^2}/{ 74.88} = 0.227

{(77 - 81.12)^2}/{ 81.12} = 0.209

{(65 - 75.36)^2}/{ 75.36} = 1.424

{(92 - 81.64)^2}{ 81.64} = 1.315

5) The significance level is set at α=0.05 for df = (4 - 1) (2 - 1) =3

degrees of freedom.

6) The critical region for this test is χ² = χ² >7.815

7) Test Statistics

χ²=i=∑(O ij −Eij )2/Eij

=0.171+0.263+0.227+1.424+0.158+0.242+0.209+1.315

= 4.009

8) Conclusion

As the calculated value χ² =4.009 does not lie in the critical region ≤χ² =7.815, null hypothesis is not rejected.

Therefore, we conclude that there is not enough evidence to accept the alternate hypothesis , at the α=0.05 significance level.

The p-value for the test at χ²= 4.009 is 0.2604

5 0
3 years ago
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