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ohaa [14]
3 years ago
5

Helppp im not sure about this one

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0
There’s no question here!
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hree different stocks were ordered. The purchase prices were 8 ⅜ dollars, 12 ⅛ dollars and 15 ⅜ dollars.how much was paid for al
Murljashka [212]
When you add all of the totals together your total amount will be $35.875
8 0
2 years ago
Read 2 more answers
Faucet A flows at a rate of 100 liters per 5 minutes and Faucet B flows at a rate of 100 liters per 4 minutes into an empty pool
Dmitriy789 [7]

Answer:

It will take both faucets 200 minutes to fill a pool with 9,000 liters of water

Step-by-step explanation:

Here, we want to know the time it will take for both faucets to fill a pool with 9,000 liters of water

What we need here is to have a joint rate for both faucets;

For the first faucet, we have a rate of 100 liters per 5 minutes so this means in a minute;

100/5 = 20 liters per minute

For the second faucet, the per minute rate will be 100/4 = 25 liters per minute

So therefore, the joint rate will be;

25 liters per minute + 20 liters per minute = 45 liters per minute

So the time needed to fill 9,000 liters of water in a pool will be ;

9000 liters/ 45 liters per minute = 200 minutes

8 0
3 years ago
A triangle has sides with lengths of 6 inches, 8 inches is it a right triangle? ​
My name is Ann [436]

Answer:

Yes

Step-by-step explanation:

8²+6²=100

√100

=10

6 0
3 years ago
6. A home repair crew charges seventy-five dollars per day plus two
ludmilkaskok [199]

Answer:

6 hours

Step-by-step explanation:

all you do is 10 divided by 6 then 0 -3-3-6-6-5-6 and you gt 10

6 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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