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ohaa [14]
3 years ago
5

Helppp im not sure about this one

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0
There’s no question here!
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Katlyn made 4 dresses with 7 yards of fabric how many yards of fadric did she use 1 dress
Ludmilka [50]

To solve this equation with algebra

4/7 = 1/x

(4/7)x = (1/x)x

4x/7 = 1

(4x/7)7 = 1(7)

4x = 7

4x/4 = 7/4

x = 1.75

1.75 yards of fabric are needed to make 1 dress.

Hope this helps! <3

5 0
3 years ago
The volume of a rectangular prism is 5058 cubic inches.
astra-53 [7]

Answer:

412in

Step-by-step explanation:

5 0
3 years ago
What is 56/18 in simplest form
Triss [41]

Answer:

The answer in the simplest form would be 28/9 or 3 1/9

Step-by-step explanation:

Very simple you would divide the 56 and the 18 by 2 and you get 28/9.

or you could change it to a improper fraction in that case it would be 3 1/9

6 0
3 years ago
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Which name accurately describes the figure shown below and why?
cestrela7 [59]

Answer:

quadrilateral, trapezoid

Step-by-step explanation:

ummmmmmm knowledge is my explanation :)

6 0
3 years ago
Read 2 more answers
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
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