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ankoles [38]
3 years ago
12

if the corresponding sides of 2 quadrilaterals are propotional, then the 2 quadrilaterals must be similar

Mathematics
1 answer:
den301095 [7]3 years ago
5 0

Answer:

False

Step-by-step explanation:

A square and a parallelogram could have proportional sides but the angles would not be the same

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What does this mean 4x + 6y=9<br> 12x + 18y=27
drek231 [11]

Answer: Infinite solutions

Step-by-step explanation:

Solve4x+6y=9for x:

4x+6y=9

4x+6y+−6y=9+−6y(Add -6y to both sides)

4x=−6y+9

4x /4 = −6y+9 /4

(Divide both sides by 4)

x= −3 /2 y+ 9 /4

Substitute

−3 /2 y+ 9 /4

for x in 12x+18y=27:

12x+18y=27

12( −3 /2 y+ 9 /4 )+18y=27

27=27(Simplify both sides of the equation)

27+−27=27+−27(Add -27 to both sides)

0=0

8 0
3 years ago
I don’t know how to do it
Gekata [30.6K]
The large rectangle is 10*20, or 200
the "hole" in the middle is 6*14, or 84
200-84=116, your answer
4 0
3 years ago
this is a hard math question the volume of a prism is the product of its height and area of its base, v = bh. a rectangular pris
Lerok [7]
V = bh
16y^4 + 16y^3 + 48y^2 = 16y^2(y^2 + y + 3)
Therefore, the prism has a base area of 16y^2 square units and height of y^2 + y + 3 units
8 0
3 years ago
ILL GIVE BRAINLIEST AND EVERYTHING ELSEEE HELP
Elenna [48]

Answer:

3x+18

Step-by-step explanation:

multiply it out to get 3x+18

8 0
3 years ago
Read 2 more answers
One root of f(x) = 2x3 9x2 7x – 6 is –3. explain how to find the factors of the polynomial.
m_a_m_a [10]
<span>We have the following polynomial:

f(x)=2x^{3}+9x^{2}+7x-6

The problem states that one root is -3. Thus, it is true that (x+3) is a factor of the polynomial. Given that this is fulfilled, it is also true that:

</span>f(x)=(x+3)Q(x) \therefore Q(x)=\frac{f(x)}{x+3} \\ \\ where \ Q(x) \ has \ a \ degree \ of \ 2<span>

We can find Q(x) by applying Ruffini's rule, thus:

</span>\ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ 7 \ \ \ \ \ \ -6  \\ -3 \\ \rule{50mm}{0.1mm} \\ \ {} \ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 3 \ \ \ \ \ -2 \ \ \ \ \ \ \ \ 0<span>

Therefore:

Q(x)=2x^{2}+3x-2

The roots of this polynomial can be get as follows:

x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \rightarrow x_{12}=\frac{-3\pm\sqrt{3^2-4(2)(-2)}}{2(2)}\\x_{1}=\frac{1}{2};\ x_{2}=-2

These are the roots along with -3. Finally, the factored polynomial can be written as follows:

f(x)=(x+3)(x+2)(2x-1)</span>
4 0
4 years ago
Read 2 more answers
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