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3 years ago

12

if the corresponding sides of 2 quadrilaterals are propotional, then the 2 quadrilaterals must be similar

1 answer:

den301095 [7]3 years ago

5 0

Answer:

False

Step-by-step explanation:

A square and a parallelogram could have proportional sides but the angles would not be the same

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An architect is constructing a model building by using a ratio os 1:300. If the height of the scale model is 3 1/2 inches what i

atroni [7]

$\bf \cfrac{model}{actual}\qquad 1:300\qquad \cfrac{1}{300}\qquad \qquad \cfrac{3\frac{1}{2}}{a}=\cfrac{1}{300}\implies \cfrac{\frac{3\cdot 2+1}{2}}{a}=\cfrac{1}{300}
\\\\\\
\cfrac{\quad \frac{7}{2}\quad }{a}=\cfrac{1}{300}\implies \cfrac{\quad \frac{7}{2}\cdot 300\quad }{1}=a\implies 1050=a$

7 0

3 years ago

prove “if two angles of one triangle are congruent to two angles of a second triangle, the the third angles of the triangles are

arsen [322]

Assume that,

The two angles of one triangle are congruent to two angles of a second triangle.

To prove: The third angles of the triangles are congruent.

Since, two angles of one triangle are congruent to two angles of a second triangle.

Therefore,

$\begin{gathered} \angle C=\angle F \\ \angle A=\angle D \end{gathered}$

Adding these two we get,

$\begin{gathered} \angle C+\angle A=\angle F+\angle D \\ 180-\angle B=180-\angle E\text{ (Using angle sum property of a triangle)} \end{gathered}$

Cancelling 180 on both sides, we get

$\begin{gathered} \angle B=\angle E \\ \therefore\angle B\cong\angle E \end{gathered}$

Hence, if two angles of one triangle are congruent to two angles of a second triangle, the the third angles of the triangles are congruent.

3 0

1 year ago

The price of a pair of shoes is $45.90. The sales-tax rate is 5 percent. How much sales tax do you need to pay?

Airida [17]

45.90*0.05=2.295. The answer is $2.30 when you round it off.

5 0

3 years ago

I will give you brainiest what is 3+3 go fast and what is 4+4

lina2011 [118]

Answer:

3+3=6 , 4+4=8

Step-by-step explanation: Brainliest pls

5 0

2 years ago

Calculate the number of ways that the coach can assign the 4 positions to his 16 players.

Natali5045456 [20]

The number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways

<h3>How to calculate the permutation</h3>

The formula for permutation is given as;

Permutation = $\frac{n!}{(n - r)!}$

n = 16

r =4

Permutation = $\frac{16!}{12!}$

Permutation = $\frac{16 *15*14*13*12*11*10*9*8*7*6*5*4*3*2*1}{12*11*10*9*8*7*6*5*4*3*2*1}$

Permutation = 43, 680 ways

Thus, the number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways

Learn more about permutation here:

brainly.com/question/12468032

#SPJ1

8 0

1 year ago