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3 years ago

I am back on you tube . my channel name - superio s // subscribe and leave a comment

Mathematics

1 answer:

Elena-2011 [213]3 years ago

4 0

Answer:

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Define a variable , write an inequality , and solve the problem:

Lady bird [3.3K]

Answer:

Step-by-step explanation:

$n-4\le 8\\ \\ n\le 12$

8 0

3 years ago

Use the quadratic formula to solve the equation: 8x(x - 2) - 20 = 5x(x - 4)

FromTheMoon [43]

Answer: $x = 2, -\frac{10}{3}$

Write the equation in standard form: $ax^{2} + bx + c = 0$ .

$8x(x - 2) - 20 = 5x(x - 4)\\\\8x^{2} - 16x - 20 = 5x^{2} - 20x\\\\3x^{2} - 16x - 20 = -20x\\\\3x^{2} + 4x -20 = 0$

Use the quadratic formula. <em>(+-) = </em>±

$\frac{-b (+-) \sqrt{b^{2} - 4ac } }{2a}$

Substitute in the values, where a = 3, b = 4, and c = -20, and simplify.

$\frac{-4(+-)\sqrt{(4)^{2} - 4(3)(-20)} }{2(3)} \\\\\frac{-4(+-)\sqrt{16 + 240} }{6}} \\\\\frac{-4(+-)\sqrt{256} }{6} \\\\\frac{-4(+-)16}{6} \\\\\frac{-4 + 16}{6}, \frac{-4 - 16}{6} \\\\\frac{12}{6}, \frac{-20}{6} \\\\2, -\frac{10}{3}$

$x = 2, -\frac{10}{3}$

3 0

4 years ago

a shop owner bought 30 folders and some journals.he paid $82.50 for the folders.Each journal costs 10 times as much as a folder

NeTakaya

To solve this one just take 82.50/30=2.75 we use these numbers because we need to divide the total price by the amount bought to see the unit price. Next we take 2.75*10 because the folders are 10x cheaper then the journals which is 27.5. So we now know that each journal costed 27.5

Enjoy!=)

7 0

3 years ago

Read 2 more answers

A - 6 - 6a = 4<br><br> find the value of a

DaniilM [7]

Answer:

-2

Step-by-step explanation:

a - 6 - 6a = 4

a-6a=10

-5a=10

a=10/-5

a=-2

8 0

3 years ago

Read 2 more answers

Help to solve the equation

PIT_PIT [208]

Answer:

n = -1.25

Step-by-step explanation:

S(ABCD) = AB × AD

S(ABCD) = 2n × (4n + 5)

S(ABCD) = CD × AD

2n × (4n + 5) = CD × (4n + 5)

n = -1.25

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5 0

2 years ago

I am back on you tube . my channel name - superio s // subscribe and leave a comment​

I am back on you tube . my channel name - superio s // subscribe and leave a comment