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Maru [420]
3 years ago
8

a beaker holds 50mL of a liquid.How many centiliters does the beaker hold? a.5000cL b.5cL c.5000cL d.500cL

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

Your answer is 5cl

Step-by-step explanation:

This is because of King Henry Died by Drinking Chocolate Milk (Kilometers,Hectometers, Decameters, Base(Liters,Meters, and Grams) Decimeters, Centimeters and Millimeters). So when you have 50 milliliters, milliliters is one place away from centiliters so you move the decimal forward one place.

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Are 12:14 and 60:70 equivalent ratios?<br><br> yes<br> no
NNADVOKAT [17]

Answer:

Yes, they are equalent

Step-by-step explanation:

12:14 = 6:7

60:70 =6:7

both can be simplified to 6:7

5 0
3 years ago
What is the value of (f*g)(-5)<br> f(x)=2x+1 ; g(x)=x^2
nikitadnepr [17]
F(-5) = 2(-5) + 1 = -9
g(-5) = (-5)^2 = 25

(f*g)(-5) = -9(25) = -225
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How to write a quadratic form vertex form to standard form
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Www.virtualnerd.com/algebra-2/quadratics/transforming-functions/vertex-form/convert-vertex-to-standa...

This will help you find what your looking for 
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3 years ago
Find the distance between (3,-3) and (2,7)
yarga [219]

Answer:

\sqrt{101} = D

Step-by-step explanation:

Method #1

We can draw a <em>right triangle</em> on the graph upon where the points are located and use the Pythagorean Theorem:

{a}^{2} + {b}^{2} = {c}^{2}

{1}^{2} + {10}^{2} = {c}^{2}

1 + 100 = {c}^{2}

101 = {c}^{2}

\sqrt{101} = c

* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.

_______________________________________________

Method #2

Or, we can use the Distance Formula:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

[2, 7] [3, −3]

\sqrt{[-3 + 2]^{2} + [3 + 7]^{2}} = D

\sqrt{[-1]^{2} + 10^{2}} = D

\sqrt{1 + 100} = D

\sqrt{101} = D

** You see? It does not matter which method you choose, as long as you are doing the work correctly.

I am delighted to assist you anytime.

5 0
2 years ago
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