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lisov135 [29]
3 years ago
9

What is the unknown number in sequence 2​

Mathematics
1 answer:
anzhelika [568]3 years ago
4 0
<h3>Answer:</h3><h3>72 </h3><h3>Step-by-step explanation:</h3><h3>form the table it is shown that 5 was skipped to 6 </h3><h3>so to get term 5 </h3><h3> we say if 48-36=12 and 36-26=12 ......in A.P series </h3><h3>so the difference is 12 </h3><h3>therefore the 5th term is 48+12 = 60 </h3><h2>and 6th term is 60+12= 72 </h2>
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A cable for a power transformer forms
posledela

Answer:

32 ft

Step-by-step explanation:

From the diagram, the side opposite the 60° angle is 28 feet.

We are looking for the approximate length of the cable.

The approximate length of the cable is the hypotenuse of the triangle shown.

Recall the sine ratio from SOH-CAH-TOA

Which means Sine of the angle is Opposite/Hypotenuse

Let the hypotenuse be h, then we have:

\sin(60) =  \frac{28}{h}

0.866 =  \frac{28}{h}

h =  \frac{28}{0.866}

h = 32.33

The length of the cable is approximately 32 feet

3 0
3 years ago
(7s – 8s⁴ – 3) + (-4s – 6s⁴ – 2s²)
klasskru [66]

The simplified expression is: -14s⁴-2s²+3s-3.

First group all the like terms together.

(-8s⁴)+(-6s⁴)=-14s

-2s

7s+(-4s)=3s

-3

Then put the expression back together, starting with the term that has the largest exponent, then working your way down. You would then get: -14s⁴-2s²+3s-3.

4 0
3 years ago
Read 2 more answers
Describe how you could draw a diagram for a problem about finding the total length for two strings, 15 inches long and 7 inches
Varvara68 [4.7K]
Two strings are 15 inches and 7 inches long.

You could draw a diagram that has two rulers (that are longer than 12 inches).

Draw a piece of string that is exactly 15 inches on one ruler.
Draw another piece of string on the other ruler at exactly 7 inches.

Then you can find the total length of the two strings by adding 15 and 7 inches.
15 + 7 = 22

The total length of both the strings is 22 inches. You can draw a ruler and a piece of string on it at 22 inches.
5 0
3 years ago
What is f(x) = 3log(x+5)=2
trasher [3.6K]

Answer:

x=10^{\frac{2}{3}}-5

Step-by-step explanation:

3 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
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