My solution to the problem is as follows:
EC = 15 ... draw CF = 6 (radius) ...use Pythagorean theorem to find EF.
EF^2 + CF^2 = EC^2
EF^2 = 15^2 - 6^2 = 189 .... EF = sq root 189
triangle GDE is similar to CFE ... thus proportional
GD / ED = CF / EF
GD / 18 = 6 / (sq root 189)
<span>GD = 108 / (sq root 189)
I hope my answer has come to your help. God bless and have a nice day ahead!
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Step-by-step explanation:
If we let the width be w, then the length is w+3.5.
This means that w(w+3.5)=11
w^2 + 3.5w - 11 = 0
2w^2 + 7w - 22 = 0 (multiply both sides by 2)
(2w+11)(w-2)=0
w = -11/2 or w = 2 (disregard w = -11/2 as distance is positive)
This means that w=2, and thus the length is 2+3.5=5.5
Answer:
Step-by-step explanation:
Answer:
log(4)
Step-by-step explanation:
log(2) + log(2)
log(2×2)
log(4)
Answer:
a₁ = 1
r = 3
Step-by-step explanation:
Since it’s a geometric series then
a₁ = 1 ( because 1 is the first term of the series)
3/1 = 9/3 = 27/9 = 81/27 = 3 then r=3.
Step-by-step explanation: