R S + 14(S) R=6 S=1/4
(6)(1/4) + 14(1/4)
1.5 + 14(1/4)
1.5 + 3.5
5
Ill give u one its B because 6x where x is the price and 2 is the price for the kids meal and it needs to stay less than $32
Answer:
The adult and the child ticket are both 8 dollars
Step-by-step explanation:
x =adult ticket price
y = child ticket price
I will assume you forget to put that they sold 2 child tickets on the second day
7x+5y=96 and 3x+2y= 40
I will use elimination. Multiply the first equation by 2 and the second equation by -5 to eliminate y
2(7x+5y)=96*2
14x + 10y = 192
The second equation
-5(3x+2y)= 40*-5
-15x -10y = -200
Add the equations together
14x + 10y = 192
-15x -10y = -200
------------------------
-x = -8
Multiply by -1
x = 8
Now we need to find y
3x+2y= 40
3(8) +2y = 40
24+2y = 40
Subtract 24 from each side
24-24 +2y = 40-24
2y = 16
Divide by 2
2y/2 =16/2
y =8
The adult and the child ticket are both 8 dollars
X^2 - 10 = 3x
X^2 - 3x - 10 = 0
(x - 5) (x + 2) = 0
x = 5 and x = -2
Answer: x = -2
After he gave one cat away he lost 1 so 3-1 is equivalent to the number 2
So you answer is 2 I hope I helped you
