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3 years ago

What’s the answer for the 1st problem

Mathematics

2 answers:

storchak [24]3 years ago

8 0

Working out:

37-5=32/4>x

Answer:

X<8

katrin [286]3 years ago

4 0

The answer is x is less than 8

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Please help me !!!!!!!!

Neko [114]

Hi :)
the correct answer is J
hope this helps!

6 0

2 years ago

Use the given graph of f to estimate the intervals on which the derivative f ' is increasing or decreasing. (Enter your answers

NARA [144]

The derivative of a function is used to determine whether the function is increasing or decreasing on any intervals in its domain.

Derivative of function f is increasing in interval (-2 , 1) and (3 , 6)

Derivative of function f is decreasing in interval (1 , 3) and (6 , 9)

If f′(x) > 0 at each point in an interval , then the function is said to be increasing in that interval.

If f′(x) < 0 at each point in an interval , then the function is said to be decreasing on that interval.

By observing graph, it is observed that slope of function f is positive in interval (-2 , 1) and (3 , 6) . Hence, derivative of function f is increasing in interval (-2 , 1) and (3 , 6)

By observing graph, it is observed that slope of function f is negative in interval (1 , 3) and (6 , 9) . Hence, derivative of function f is decreasing in interval (1 , 3) and (6 , 9).

Learn more:

brainly.com/question/14330051

5 0

1 year ago

Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given freque

maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals Frequency

100 - 199 24

200 - 299 90

300 - 399 27

400 - 499 1

500 - 599 4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

99.5 - 199.5

199.5 - 299.5

299.5 - 399.5

399.5 - 499.5

499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

$\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{99.5+199.5}{2}\\\\=149.5$

$\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{199.5+299.5}{2}\\\\=249.5$

$\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{299.5+399.5}{2}\\\\=349.5$

$\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{399.5+499.5}{2}\\\\=449.5$

$\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{499.5+599.5}{2}\\\\=549.5$

The number of individuals included in the summary is the sum of all frequencies.

$\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146$

Thus, the number of individuals included in the summary is 146.

3 0

2 years ago

Read 2 more answers

Whole number 6 is equal to ?/3

Ugo [173]

Step-by-step explanation:

That means 6/3 is equivalent to 2 wholes! When the numerator is divisible by the denominator, the fraction is equivalent a whole number. If the numerator is equal to the denominator, you will always have one whole, or 1.

5 0

2 years ago

sum of the age of son and his father is60 and the six year ago the age of father is five time the son what is the age son ?

natali 33 [55]

Step-by-step explanation:

...hope it help u.... ..

6 0

3 years ago