Given expression:
.






<h3>Therefore, correct option is B option : B.4x^4</h3>
M= y2-y1/x2-x1
Make sure you put it in the form
Hope this helps!!:))
First off, let's take a look at what these numbers are:
Real numbers: It can be any numbers,both rational and irrational.
Natural numbers: The number has to be integer and positive.
Integers: A number without fraction or demical place.
Whole number: The number has to be natural and cannot be negative.
Therefore, as 12 is a positive number with no demical place or fraction, it is real numbers,integers, whole numbers, and natural numbers.
Hope it helps!