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riadik2000 [5.3K]
3 years ago
7

As part of the underwriting process for insurance, each prospective policyholder is tested for high blood pressure. Let X repres

ent the number of tests completed when the first person with high blood pressure is found. The expected value of X is 12.5. Calculate the probability that the sixth person tested is the first one with high blood pressure.
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

0.053

Step-by-step explanation:

This is a geometric distribution problem.

I'm geometric distribution problem,

E(X) = 1/p

Where;

E(X) is expected value and p is probability of success

Thus;

1/p = 12.5

p = 1/12.5

p = 0.08

Now, to find the probability that the sixth person tested is the first one with high blood pressure, we will use the probability formula in geometric distribution which is;

P(X = k) = qⁿ•p

q = 1 - p

q = 1 - 0.08

q = 0.92

Thus;probability that the sixth person tested is the first one with high blood pressure will be expressed as;

P(X > 5) = (0.92^(5)) × 0.08

P(X > 5) = 0.053

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Step-by-step explanation:

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The LCM in this example is 60. In order to have exactly 60 forks and 60 spoons, Jasmine will need to buy 6 packages of forks [60 ÷ 10 = 6] and 5 packages of spoons [60 ÷ 12 = 5].

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Write 0.216 as a rational number in lowest terms
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Step-by-step explanation:

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=\frac{216}{1000}

216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

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=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

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\mathrm{Cancel\:the\:common\:factor:}\:8

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Hence, the correct answer is =\frac{27}{125}

6 0
3 years ago
While driving from​ Chicago, Brent had a visibility problem due to the fog. After 1 1/2
liq [111]
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2) Let x be the speed of 1 snail, 
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Hope I helped :) 
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