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Lelechka [254]
3 years ago
8

Shirley wants to buy a skateboard for $64. She has $98 in her account. She spent $10.85 to buy stationary. She also wants to buy

some cookies for $1.65 each. What is the maximum number of cookies, n, that Shirley can buy so that she has enough money left to buy the skateboard? a. n ≥ 14 b. n ≤ 16 c.n ≤ 14 d.n ≥ 16
Mathematics
2 answers:
klemol [59]3 years ago
5 0

she had 98 but spent 10.85 so she now has:

98-10.85 = 87.15

skateboard cost 64

87.15 -64 = 23.15 is what she can spend on cookies

23.15 / 1.65 = 14.03 she can't buy more than 14 cookies

 so answer is c. n ≤ 14

malfutka [58]3 years ago
4 0

Answer:

Im answering so can give him/ or her brainliest.

Step-by-step explanation:

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I need help learning how to solve this problem please.
Radda [10]

we have 4 gals, Stephanie, Andrea, Emily and  Becca.

btw the end point should be (-6, -7) and the start point is (8, 6).

so, if we know the distance between those two points, we can just cut it in 4 equal pieces and each gal will be driving a piece.

now, Emily's turn is after Andrea, BUT, we had first Stephenie driving ¼ of the way, then Andrea driving ¼ of the way too, but after ¼+¼, Emily comes on, but ¼+¼ is really 1/2, so when Emily starts, is really half-way through, or the midpoint of that distance.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\stackrel{\textit{Hometown}}{(\stackrel{x_1}{8}~,~\stackrel{y_1}{6})}\qquad
\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-6+8}{2}~~,~~\cfrac{-7+6}{2} \right)\implies \left(\cfrac{2}{2}~,~\cfrac{-1}{2} \right)\implies \stackrel{\textit{Emily starts off}}{\left(1~,-\frac{1}{2} \right)}


Emily's turn ends ¼ of the way later, which will be pretty much half-way in between  (1, -½) and (-6, -7), so is really the midpoint of those two.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{1}~,~\stackrel{y_1}{-\frac{1}{2}})\qquad
\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}
\\\\\\
\left( \cfrac{-6+1}{2}~~,~~\cfrac{-7-\frac{1}{2}}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-14-1}{2}~}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-15}{2}~}{2} \right)
\\\\\\
\left( \cfrac{-5}{2}~,~\cfrac{-15}{4} \right)\implies \left( -2\frac{1}{2}~,~-3\frac{3}{4} \right)

8 0
3 years ago
Solve for t. f(t)=-16t^2+576​
IgorC [24]

Answer: t^2=-f-576/16

Step-by-step explanation:

Step 1. Switch the equation around:

-16t^2+576=f

Step 2. Subtract 576 from each side:

-16t^2+576-576=f-576

Step 3. Now simplify:

-16t^2=f-576

Step 4. Divide everything now by -16:

-16t^2/-16=f/-16-576/-16

Step 5. Simplify again:

t^2=-f-576/16

Hope I could help! :)

3 0
3 years ago
0.25 r – 0.125 + 0.5 r = 0.5 + r . Solve for r.
kotykmax [81]
0.25r - 0.125 + 0.5r = 0.5 + r

0.75r - 0.125 = 0.5 + r    |add 0.125 to both sides

0.75r = 0.625 + r      |subtract r from both sides

-0.25r = 0.625    |divide both sides by (-0.25)

r = - 2.5
6 0
3 years ago
A scatterplot shows a strong, positive, linear relationship between the number of rebounds a basketball team averages and the nu
JulijaS [17]

Answer:

The correct answer is wins and rebounds are correlated positively ,but we cannot decided that having more rebounds leads to more wins,on average.

Step-by-step explanation:

From the example given, the most appropriate conclusion is that, because  causation is not the same as correlation, If two variables are compared,this does not mean that one leads to the other.

An observed data is based on correlation,but for description of  causation ,we need to make experiments,as we update the  variable treatment regarding  to the changes in response variable.

8 0
3 years ago
Please answer number 2. !
soldier1979 [14.2K]

Answer: 77

Step-by-step explanation:

7 0
3 years ago
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