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Dominik [7]
2 years ago
5

The sum of a number and two is equal to negative seven. Translate this sentence to an equation and then find the number.

Mathematics
1 answer:
dimaraw [331]2 years ago
8 0

Answer: -9

Step-by-step explanation:

Given

The sum of a number and two is equal to negative 7

Suppose x is that number

\therefore x+2=-7\\\text{add -2 both sides}\\\Rightarrow x+2-2=-7-2\\\Rightarrow x=-9

So, the number is -9.

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Almost there, then everything is set! Thanks guys
faust18 [17]

Answer:

x = 50°

Step-by-step explanation:

Step 1.

180° - 80° (because there are 180 degrees in a triangle) = 100°

Step 2.

100° ÷ 2 = 50° (because the two angles on the bottom are identical, as this is an isosceles triangle - which we know because the two sides on the left and right are both the same length, 7 units)

Step 3.

Answer: x = 50°

5 0
2 years ago
$85 jeans, 7% tax what is the total cost<br>please a show work​
fgiga [73]

Answer:

<em>See below.</em>

Step-by-step explanation:

Divide to turn the percentage into a decimal.

\frac{7}{100} =0.07

Multiply to find the total amount of tax.

85*0.07=5.95

Add it to the total.

85+5.95=90.95

<em>Answer: </em>90.95<em />

<em />

<em>:)</em>

8 0
3 years ago
Read 2 more answers
Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G
Kaylis [27]

\Rightarrow

Suppose first that H\subset G is a normal subgroup. Then by definition we must have for all a\in H, xax^{-1} \in H for every x\in G. Let a\in G and choose (ab)\in aH (b\in H). By hypothesis we have aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H, i.e. aba^{-1}=c for some c\in H, thus ab=ca \in Ha. So we have aH\subset Ha. You can prove Ha\subset aH in the same way.

\Leftarrow

Suppose aH=Ha for all a\in G. Let h\in H, we have to prove  aha^{-1} \in H for every a\in G. So, let a\in G. We have that ha^{-1} =a^{-1}h' for some h'\in H (by the hypothesis). hence we have aha^{-1}=h' \in H. Because a was chosen arbitrarily  we have the desired .

 

5 0
2 years ago
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
3 years ago
16 multiply 7/8 in simplest
denpristay [2]
Answer: 14

= 16 x (7/8)
= 8 goes into 16 2 times
= 2 x 7
= 14
5 0
2 years ago
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