For x > 2, you would circle the 2, but you would not shade it in because it is greater than/ less than, not greater than or equal to/less than or equal to. From there on, you would move it to the right, because here x is greater than 2, and the numbers to the right of 2 are greater than two.
For x < 2, you would again circle the 2, but don't shade it in. And then you would make a line heading towards the left, because the numbers to the left of 2 are smaller than 2, and here, x is smaller than 2, since 2 is greater.
A value that is not the solution to either inequality is 2. 2 is not greater than 2, and 2 is not less than 2.
Answer:
Points H, J, G, and K
Step-by-step explanation:
For quadrats the right top is 1
left top is 2
left bottom is 3
right bottom is 4
and it is asking for the forth one so look at the right bottom "square"
G and K are on the line but that still makes them part of a Quadratic Just they get to be part of 2 of them like...
G is 3 and 4
K is 1 and 4
Answer:
see explanation
Step-by-step explanation:
Given that y varies inversely as x then the equation relating them is
y = 
← k is the constant of variation
To find k use the condition y = 5 , x = 21
k = yx = 5 × 21 = 105
y = 
← equation of variation
When x = 10, then
y = 
= 10.5
Answer:
(3, - 1)
Step-by-step explanation:
5x - 4y = -11
2x + 3y = -9
Multiply the top equation by 2 and the bottom equation by - 5 to cancel out the x's.
10x - 8y = - 22
- 10x - 15y = 45
Cancel out x's.
-8y = - 22
- 15y = 45
Add like terms.
- 23y = 23
Can't have a negative variable to flip them.
-23 = 23y
Divide.
y = - 1
Input y into one of the equations and solve for x.
2x + 3(-1) = -9
Simplify.
2x -3 = -9
Cancel out -3 by adding 3.
2x = -6
Divide.
x - -3
