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2 years ago

The sum of a number and two is equal to negative seven. Translate this sentence to an equation and then find the number.

Mathematics

1 answer:

dimaraw [331]2 years ago

8 0

Answer: -9

Step-by-step explanation:

Given

The sum of a number and two is equal to negative 7

Suppose x is that number

$\therefore x+2=-7\\\text{add -2 both sides}\\\Rightarrow x+2-2=-7-2\\\Rightarrow x=-9$

So, the number is $-9$ .

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Almost there, then everything is set! Thanks guys

faust18 [17]

Answer:

x = 50°

Step-by-step explanation:

Step 1.

180° - 80° (because there are 180 degrees in a triangle) = 100°

Step 2.

100° ÷ 2 = 50° (because the two angles on the bottom are identical, as this is an isosceles triangle - which we know because the two sides on the left and right are both the same length, 7 units)

Step 3.

Answer: x = 50°

5 0

2 years ago

$85 jeans, 7% tax what is the total cost please a show work

fgiga [73]

Answer:

See below.

Step-by-step explanation:

Divide to turn the percentage into a decimal.

$\frac{7}{100} =0.07$

Multiply to find the total amount of tax.

$85*0.07=5.95$

Add it to the total.

$85+5.95=90.95$

Answer:  $90.95$ 

:)

8 0

3 years ago

Read 2 more answers

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .