All categories

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics

1 answer:

vesna_86 [32]3 years ago

5 0

x⁴ - 625 = (x² -25)(x² +25) = (x-5)(x+5)(x+5i)(x-5i)

You might be interested in

I need help!!!<br> please XD

BabaBlast [244]

Answer:

with? TwT mental? physical?

Step-by-step explanation:

5 0

3 years ago

Write an expression for: the product of 4 and a number. Use x as the variable. Who ever gets it correct first gets brainliest.

maksim [4K]

X(4*1) because I’m just doing what I’m told.

7 0

2 years ago

Plss. pa answers ?<br><br>thanks po<br><br>

Lana71 [14]

Answer:

<h3>Graph 3</h3>

Line starting at x = -2

<u>Domain</u>: x ≥ -2
<u>Range</u>: y ≥ 0

<h3>Graph 4</h3>

Vertical line

<u>Domain</u>: x = 3
<u>Range</u>: y = any real number

<h3>Graph 5</h3>

Quadratic function with negative leading coefficient and max value of 3

<u>Domain</u>: x = any real number
<u>Range</u>: y ≤ 3

<h3>Graph 6</h3>

Curve with non-negative domain and min value of -2

<u>Domain</u>: x ≥ 0
<u>Range</u>: y ≥ -2

<h3>Graph 7</h3>

Line with no restriction

<u>Domain</u>: x = any real number
<u>Range</u>: y = any real number

<h3>Graph 8</h3>

Quadratic function with positive leading coefficient and min value of 4

<u>Domain</u>: x = any real number
<u>Range</u>: y ≥ 4

<h3>Graph 9</h3>

Parabola with restriction at x = -4

<u>Domain</u>: x = any real number except -4
<u>Range</u>: y = any real number

<h3>Graph 10</h3>

Square root function with star point (2, 0)

<u>Domain</u>: x ≥ 2
<u>Range</u>: y ≥ 0

5 0

2 years ago

The sales function for a Super Mario Kart Video Game, d(x), after x years is represented by d(x)=30000\left(0.92)^{x}. To the ne

vitfil [10]

Answer:

SO you want me to figure out from year 2 or year4?

Step-by-step explanation:

7 0

2 years ago

a positive number is 5 times less than another positive number. Six times the lesser number plus 3 times the greater is 3. Find

IgorLugansk [536]

<h2>Greetings!</h2>

Answer:

One number is $\frac{5}{7}$ and the other number is $\frac{1}{7}$

Step-by-step explanation:

Let x be the smaller number and y be the bigger number.

x = x

y = 5x

6x + 3y = 3

6x + (3 * 5x) = 3

6x + 15x = 3

(÷3)

2x + 5x = 1

7x = 1

x = $\frac{1}{7}$

6x + 3y = 3

6( $\frac{1}{7}$ ) + 3y = 3

$\frac{6}{7}$ + 3y = 3

3y = 3 - $\frac{6}{7}$

3y = $\frac{15}{7}$

Divide both sides by 3 to get 1y:

y = $\frac{5}{7}$

So one number is $\frac{5}{7}$ and the other number is $\frac{1}{7}$

<h2>Hope this helps!</h2>

5 0

2 years ago