To ease your problem, consider "L" as you x-axis
Then the coordinate become:
A(- 4 , 3) and B(1 , 2) [you notice that just the y's changed]
This is a reflection problem.
Reflect point B across the river line "L" to get B', symmetric of B about L.
The coordinates of B'(1 , -1) [remember L is our new x-axis]
JOIN A to B' . AB' intersect L, say in H
We have to find the shortest way such that AH + HB = shortest.
But HB = HB' (symmetry about L) , then I can write instead of
AH + HB →→ AH + HB'. This is the shortest since the shortest distance between 2 points is the straight line and H is the point requiered
Answer:
The second option (choice b)
Step-by-step explanation:
At -1 is the line starts going up so its increasing. 2 shows that the line is starting to decrease so it would be between -1 and 1 where the line is increasing on the graph.
Answer:
D: 3(x + 5)(x + 5)
Step-by-step explanation:
Try multiplying the last answer choice (D); the result is 3(x^2 + 10x + 25), or
3(x + 5)(x + 5).
