Answer: system 2 (5,0) and system 3 (-1 2)
2x-6y=10 3x-y=-5
x+8y=5 x+4y=7
Step-by-step explanation:
Solve each system. Then drag each one to the column headed by a point which could be its solution. (5,y) or (x,2)
system 1
2x - 2y =12
-2x-3y = -22
solve simultaneous equation
2x - 2y =12
-2x-3y = -22
add the equations gives
2x +(-2x) =0
-2y+(-3y) =-5y
12+ (-22) = -10
-5y =-10
y =2
2x -2(2) =12
2x-4 =12
2x = 12+4
x= 16/2 =8 x=8 and y =2 = (8,2)
system 2
2x-6y=10 *(-1) = -2x + 6y =-10
x+8y=5 *(2) = 2x + 16y =10 add the equations
22y =0 y =0
x : 2x - 6(0) =10
x = 10/2 = 5
(5, 0)
system 3
3x-y=-5 *(-1) = -3x + y =5
x+4y=7 * (3) = 3x + 12y = 21
add the equations = 13y = 26 y = 2
3x -2 =-5 = 3x = -3 =x =-1
(-1 2) answer
system 4
x+y=2 *(-2) = -2x -2y = -4
2x+y=13 *(1) = 2x +y = 13
add the two equations = -y =9
y = -9
substitute 2x-9= 13= 2x =22 x =11
(11 -9)
