Formula1" title="\int\{-2+(x^{2} +3x)^(6/5) - x^3} \, dx" alt="\int\{-2+(x^{2} +3x)^(6/5) - x^3} \, dx" align="absmiddle" class="latex-formula">
1 answer:
Apply sum rule:
- 2dx + (x^2 +3x) 6/5dx = x^3dx
2dx = 2x
(x^2 + 3x) 6/5dx = 6/5 (x^3/3 + 3x^2/2)
x^3dx = x^4/4
-2x + 6/5 (x^3/3 + 3x^2/2) - x^4/4
Add constant
-2x + 6/5 (x^3/3 + 3x^2/2) - x^4/4 + c
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