Answer:
Explained below.
Step-by-step explanation:
Consider the series is a set of first 6 natural numbers.
Sum of first <em>n</em> terms is:
Consider the series is an arithmetic sequence.
Sum of first <em>n</em> terms is:
![S_{n}=\frac{n}{2} [2a+(n-1)d]](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%20%5B2a%2B%28n-1%29d%5D)
Here<em>,</em>
<em>a</em> = first term
<em>d</em> = common difference
Consider the series is an geometric sequence.
Sum of first <em>n</em> terms is:
Here<em>,</em>
<em>a₁</em> = first term
<em>r</em> = common ratio
It’s (-8z^2 +8x +4y -2z)
Hope it helps
50 might be the answer because 12÷6=2 so I just multiplied 15×2 and that equaled my answer, 50
Answer: The probability of drawing a red marble the sixth time is 1/2
Step-by-step explanation:
Here is the complete question:
A box contains 10 red marbles and 10 green marbles. Sampling at random from the box five times with replacement, you have drawn a red marble all five times. What is the probability of drawing a red marble the sixth time?
Explanation:
Since the sampling at random from the box containing the marbles is with replacement, that is, after picking a marble, it is replaced before picking another one, the probability of picking a red marble is the same for each sampling. Probability, P(A) is given by the ratio of the number of favourable outcome to the total number of favourable outcome.
From the question,
Number of favourable outcome = number of red marbles =10
Total number of favourable outcome = total number of marbles = 10+10= 20
Hence, probability of drawing a red marble P(R) = 10 ÷ 20
P(R) = 1/2
Since the probability of picking a red marble is the same for each sampling, the probability of picking a red marble the sixth time is 1/2
Hey there!
If we have 12 squares and one of every 3 is a cork square, that means that 1/3 of the squares are cork. Using our keyword "of" meaning multiplication, we have:
1/3 * 12 = 12/3 = 4 cork squares
Hope this helps!
