First term, a
1
=4
Second term, a
2
=8
Common difference, d=a
2
=a
1
d=8−4=4
∴ The common difference is 4
Answer:
n + 4
Step-by-step explanation:
It´s like a normal sum, but since the number is unknown just put n.
Answer:
z≈3.16
p≈0.001
we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.
Step-by-step explanation:
As a result of step 2, we can assume normal distribution for the null hypothesis
<em>step 3:</em>
z statistic is computed as follows:
z=
where
- X is the proportion of correct answers in the test (
) - M is the expected proportion of correct answers according to the null hypothesis (0.5)
- p is the probability of correct answer (0.5)
- N is the total number of questions in the test (40)
z=
≈ 3.16
And corresponding p value for the z-statistic is p≈0.001.
Since p<0.05, we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.
Answer:
The answer to your question is the first option
Step-by-step explanation:
64
Process
1.- Find the prime factors of 64
64 2
32 2
16 2
8 2
4 2
2 2
1
64 = 2⁶
2.- Express 64 as a fractional exponent
64
3.- Simplify
64
64
64![^{1/4} = 2\sqrt[4]{2^{2}}](https://tex.z-dn.net/?f=%5E%7B1%2F4%7D%20%3D%202%5Csqrt%5B4%5D%7B2%5E%7B2%7D%7D)
4.- Result
64