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sladkih [1.3K]
3 years ago
7

X^4 a^5 / x^3 a^3 answers x^2 a^2 xa^2 x^-1 a^-2 a^2/x

Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0
Well the answer i got was a^{8}x when i multiplied
the answer i got when i added was x^{4} + \frac{ a^{5} }{ x^{3} } + a^{3}
You might be interested in
Suppose​ a, b, and c are all negative numbers. How do you find the distance between the points​ (a,b) and​ (a,c)?
Alex787 [66]

Answer:

E

Step-by-step explanation:

Let's say if b = -2 and c = -3

-2-(-3) = 1 that would be the distance between them.  If it was D then you would need absolute value.

Hope this helps!  Have a nice day!

4 0
2 years ago
If f(1)=10 and f(n)=-5f(n-1)-2 then find the value of f(4)
Flura [38]

Answer:

\large\boxed{f(4)=-1292}

Step-by-step explanation:

f(n)=-5f(n-1)-2\\\\f(1)=10\\\\f(2)=-5f(2-1)-2=-5f(1)-2\\\text{put}\ f(1)=10:\\f(2)=-5(10)-2=-50-2=-52\\\\f(3)=-5f(3-1)-2=-5f(2)-2\\\text{put}\ f(2)=-52\\f(3)=-5(-52)-2=260-2=258\\\\f(4)=-5f(4-1)-2=-5f(3)-2\\\text{put}\ f(3)=258\\f(4)=-5(258)-2=-1290-2=-1292

4 0
3 years ago
(4x5 + 9x3 - 12x8) + (8x3 - 7x + 2x5)
SSSSS [86.1K]

Answer:

-10x5 + 8x4 - 7x3 - 20x2 - x + 18

Step-by-step explanation:

8 0
3 years ago
HI I need help please <br> Its in the pictures
Brut [27]
1.

r=32\,\text{units}\\\\&#10;A=\pi\cdot r^2=\pi\cdot32^2=1024\pi\,\,\text{units}^2

Answer D.

2.
From secant theorem, we know, that:

|AE|\cdot|BE|=|DE|\cdot|CE|

and from picture:

|BE|=x+1\\\\|CE|=x+4\\\\|AE|=11+x+1=x+12\\\\|DE|=1+x+4=x+5

So we can calculate:

|AE|\cdot|BE|=|DE|\cdot|CE|\\\\(x+12)\cdot(x+1)=(x+5)\cdot(x+4)\\\\&#10;x^2+12x+x+12=x^2+5x+4x+20\\\\&#10;x^2+13x+12=x^2+9x+20\quad|-x^2\\\\13x+12=9x+20\quad|-9x\\\\4x+12=20\quad|-12\\\\4x=8\quad|:4\\\\\boxed{x=2}
8 0
3 years ago
Use the Theorem of Pappus to find the volume of the solid formed by revolving the region bounded by the graphs ofy=x, y=10, and
Pepsi [2]

Answer:

C) 2094.40

nearest answer.

Step-by-step explanation:

Since the given region is bounded by y = x, y = 10 and x = 0

⇒ 0 ≤ y ≤ 10

Radius and Height are 'y'

∴ The required volume

= ∫₀¹⁰2π(radius)(height)dy

= ∫₀¹⁰2π (y) (y) dy

= ∫₀¹⁰2π y² dy

= 2π ∫₀¹⁰ y² dy

Integrate y

= 2\pi [\frac{y^3}{3}]_0^{10}

= 2\pi [\frac{10^3}{3} - 0]

= \frac{2000}{3} \pi

where π is 3.142

= 2,094.66

5 0
3 years ago
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