<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:
6 times 10^3
Step-by-step explanation:
You multiply 3 and 2 together and 10^7 and 10^-4 together. 3x2 is equal to 6 and 10^7 times 10^-4 is the same as 10^7-4 which is equal to 10^3. Therefore, the answer is 6 times 10^3.
If this has helped please mark as brainliest
Answer:
155+27n
Step-by-step explanation:
hope this helps
Answer:
49 students/7 teams= 7 students per team
49/7=7
i hope this work for you
and sory if im wrang
