We are given with a equation of Circle and we need to find it's radius and it's equation in standard form . But , let's recall , the standard equation of a circle is
where <em>(h,k)</em> is the centre of the circle and radius is <em>r</em> . Proceeding further ;
Collecting <em>x</em> terms , y terms and transposing the constant to RHS ;
Now , as in standard equation their is a whole square , so we need to develop a whole square in LHS , for which we will use completing the square method , as coefficient of x² and y² is 1 , so adding 121 and 36 to LHS and RHS .
On comparing this with the standard equation , we got our centre at <em>(-11,-6)</em> and radius is <em>18 units </em>
to get his wage for the next day, you would do 18x1.2, which equals 21.6, so he would now be making $21.6 per hour.
Answer:
0 i hope this helps
Step-by-step explanation:
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0
.
3x−2=0
x+4=0
Set the first factor equal to 0
and solve.
Tap for more steps...
x=23
Set the next factor equal to 0
and solve.
Tap for more steps...
x=−4
The final solution is all the values that make (3x−2)(x+4)=0
true.
x=23,−4
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